Answer:
Explanation:
According to the question
net force F = 2.20×10^6 N
displacement 
from figure , the horizontal forces are same in magnitude and opposite direction.
so , neglect these two forces.
we can take only vertical components of the force.
total force F' = F cos 19° + F cos 19°
= 2×F×cos 19° ................. (1
therefore , total work is
W = F'S
= (2F cos19)×S
Answer:
4500.5 nutritional calories per gram
Explanation:
Heat lost by the new candy = heat gained by the bomb calorimeter.
Heat gained by the bomb calorimeter = c×ΔT
where c = heat capacity of the calorimeter = 32.20 KJ/K = 32200 J/K
ΔT = change in temperature = 2.69°C = 2.69 K.
Heat gained by the bomb calorimeter = 32200 × 2.69 = 86618 J
Heat lost by the new candy = heat gained by the bomb calorimeter = 86618 J = 20702.2 calories
4.60 g of the new candy lost this amount of calories by undergoing combustion,
The amount of calories per g = 20702.2 calories/4.6 g = 4500.5 calories per gram
The value of parameter C for the function in the figure is 2.
<h3>What is amplitude of a wave?</h3>
The amplitude of a wave is the maximum displacement of the wave. It can also be described at the maximum upward displacement of a wave curve.
f(x) = Acos(x - C)
where;
- A is amplitude of the wave
- C is phase difference of the wave
<h3>What is angular frequency of a wave?</h3>
Angular frequency is the angular displacement of any element of the wave per unit time.
From the blue colored graph; at y = 1, x = -2 cm
1 = cos(2 - C)
(2 - C) = cos^(1)
(2 - C) = 0
C = 2
Thus, the value of parameter C for the function in the figure is 2.
Learn more about phase angle here: brainly.com/question/16222725
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To solve this problem we will use the Ampere-Maxwell law, which describes the magnetic fields that result from a transmitter wire or loop in electromagnetic surveys. According to Ampere-Maxwell law:
Where,
B= Magnetic Field
l = length
= Vacuum permeability
= Vacuum permittivity
Since the change in length (dl) by which the magnetic field moves is equivalent to the perimeter of the circumference and that the electric flow is the rate of change of the electric field by the area, we have to
Recall that the speed of light is equivalent to
Then replacing,
Our values are given as
Replacing we have,
Therefore the magnetic field around this circular area is
