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antoniya [11.8K]
4 years ago
14

What is the correct definition of refraction?

Physics
1 answer:
scoray [572]4 years ago
5 0

i believe it's C but i'm not completely sure

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You drop an ice cube into an insulated bottle full of water and wait for the ice cube to completely melt. The ice cube initially
AVprozaik [17]

Answer:

T_{f}  = 17º C

Explanation:

This is a calorimetry problem, where heat is yielded by liquid water, this heat is used first to melt all ice, let's look for the necessary heat (Q1)  

Let's reduce the magnitudes to the SI system  

      Ice m = 80.0 g (1 kg / 1000 g) = 0.080 kg  

            L = 3.33 105 J / kg  

Water  M = 860 g = 0.860 kg  

           c_{e} = 4186 J / kg ºC

    Q₁ = m L  

     Q₁ = 0.080 3.33 10⁵

     Q₁ = 2,664 10⁴ J

Now let's see what this liquid water temperature is when this heat is released  

      Q = M c_{e} ΔT = M c_{e} (T₀₁ -T_{f1})  

      Q₁ = Q  

     T_{f1} = T₀₁ - Q / M ce  

     T_{f1} = 26.0 - 2,664 10⁴ / (0.860 4186)  

     T_{f1} = 26.0 - 7.40  

     T_{f1} = 18.6 ° C  

The initial temperature of water that has just melted is T₀₂ = 0ª  

The initial temperature of the liquid water is T₀₁= 18.6  

     m c_{e} T_{f} + M c_{e} T_{1} = M c_{e} T₀₁ - m c_{e} T₀₂o2  

         T_{f} = (M To1 - m To2) / (m + M)  

         T_{f} = (0.860 18.6 - 0.080 0) / (0.080 + 0.860)  

T_{f} = 17º C

 

gg

4 0
3 years ago
Lori wants to send a box of oranges to a friend by mail. The box of oranges cannot exceed a mass of 10.222 Kg. If each orange ha
Sergeu [11.5K]

Explanation:

Given that,

The box of oranges cannot exceed a mass of 10.222 Kg if we are sending to a friend by mail.

The mass of each orange is 198 g

We know that,

1 kg = 1000 g

10.222 kg = 10.222×1000 g

Let there are n number of oranges. So,

n=\dfrac{10.222\times 1000\ g}{198\ g}\\\\n=51.92\approx 52\ \text{oranges}

It means she can send 52 oranges and it is maximum quantity.

4 0
4 years ago
(c)
lys-0071 [83]
The answer is c. Twelve wants pass an obsessive frequency of the internet
7 0
4 years ago
If a raindrop is 0.05 cm3 in volume, what would the volume of an avogadro number of raindrops be?
zhenek [66]
If a raindrop is 0.05 cm^3 in volume, then <span> the volume of an Avogadro number of raindrops be 3.011 x 10^22 cm^3. To calculate this value, we simply multiply the volume given to Avogadro's number which </span><span>represents the number of units in one mole of any substance. This has the value of 6.022 x 10^23.</span>
4 0
3 years ago
4 A car horn has a frequency of 400 Hz. The car is moving away from an
NeTakaya

Answer:

  f = 409.6 Hz,  the woman hears a higher frequency sound

Explanation:

This is a Doppler effect problem, which is described by the equation for the case of a fixed observer

          f = fo \frac{v}{v \pm v_s}

where the negative sign is for the source approaching the observer

in this case the car is the one that emits the sound and moves away from the intersection

let's calculate

          f = 400  \frac{343}{343-8}

          f = 409.6 Hz

therefore the woman hears a higher frequency sound

7 0
3 years ago
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