1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
vichka [17]
3 years ago
12

A solution has pOH 5.9

Chemistry
2 answers:
QveST [7]3 years ago
6 0

Answer:

The answer to your question is below

Explanation:

Data

pOH = 5.9

a) [OH⁻] = ?

pOH measures the [OH⁻]

Formula

pOH = -log[OH⁻]

-Substitution

5.9 = -log[OH⁻]

[OH⁻] = antilog (-5.9)

-Result

[OH⁻] = 1.26 x 10⁻⁶ M

b) [H₃O⁺]

pH + pOH = 14

-Solve for pH

pH = 14 - pOH

-Substitution

pH = 14 - 5.9

-Result

pH = 8.1

-Calculate [H₃O⁺]

pH = -log[H₃O⁺]

-Substitution

8.1 = -log[H₃O⁺]

[H₃O⁺] = antilog(-8.1)

-Result

[H₃O⁺] = 7.9 x 10⁻⁹ M

c) This solution is alkaline because the pH is higher than 7.

Karo-lina-s [1.5K]3 years ago
5 0
The answer is A
A. Poh 5.9
You might be interested in
A sample of water is heated from 60.0 °C to 75.0°C by the addition of 140 j of
kupik [55]

Mass of the water : 2.23 g

<h3>Furter explanation</h3>

Heat

Q = m.c.Δt

m= mass, g

c = heat capacity, for water : 4.18 J/g° C.

ΔT = temperature

Q= 140 J

Δt = 75 - 60 = 15

mass of the water :

\tt m=\dfrac{Q}{c.\Delta T}=\dfrac{140}{4.18\times 15}=2.23~g

5 0
3 years ago
PLEASE HELP 50 POINTS A really colorful reaction is the synthesis reaction of aluminum and iodine, often called the “Purple Haze
marysya [2.9K]

Answer:

I know that the limited reactant Al.

7 0
3 years ago
How much (mL) of a 2.0 M sodium hydroxide solution would it take to neutralize 50 mL of a 6.0 M solution of hydrochloric acid?
Tom [10]

Answer:

150ml

Explanation:

For this question,

NaOH completely dissociates. It is a strong base

HCl also completely dissociates. It is a strong acid

So we have this equation

m1v1 = m2v2 ----> equation 1

M2 = 2m

V1= ??

M2 = 6m

V2 = 50m

When we input these into equation 1, we have:

2m x v1 = 6m x 50ml

V1 = 6m x 50ml/2

V1 = 300/2

V1 = 150ml

Therefore NaOH that is required to neutralize the solution of hydrochloric acid is 150ml.

Thank you

8 0
3 years ago
What's the definition of soil composition ( 17 points ) !!! I NEED HELP NOW
Maru [420]
Soil composition refers to the nutrients and various other substances present in the soil. These are categorized into four basic categories: water, air, organic matter and minerals.
7 0
3 years ago
What is the molar mass of aluminum (Al)
Papessa [141]

Answer:

26.981539 u

Explanation:

One mole of Al atoms has a mass in grams that is numerically equivalent to the atomic mass of aluminum. The periodic table shows that the atomic mass (rounded to two decimal points) of Al is 26.98, so 1 mol of Al atoms has a mass of 26.98 g.

6 0
3 years ago
Read 2 more answers
Other questions:
  • Prions are proteins with the ability to generate more prions by causing other proteins to misfold into a similar shape. Since pr
    14·1 answer
  • In a 1.0-liter container there are, at equilibrium, 0.10 mole h2, 0.20 mole n2, and 0.40 mole nh3. what is the value of kc for t
    5·1 answer
  • __________ bonds form between the oxygen and hydrogen within water molecules, whereas __________ bonds form between different wa
    9·1 answer
  • It is often necessary to prepare a dilute solution from a more concentrated solution rather than starting from a solid and just
    13·1 answer
  • Sonar is a technology that uses sound waves to calculate the distance to an object. Explain why you think sonar is useful for sc
    7·1 answer
  • When light cannot travel trough a material, the light has been
    12·1 answer
  • What are the 5 steps that a star will go through to try<br> to maintain equilibrium?
    9·1 answer
  • What is a personal factor of resilience?
    12·1 answer
  • Can matter be created or<br> destroyed?<br><br> Yes or No
    15·2 answers
  • Which instrument below is used to measure an intensive property?
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!