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vichka [17]
4 years ago
12

A solution has pOH 5.9

Chemistry
2 answers:
QveST [7]4 years ago
6 0

Answer:

The answer to your question is below

Explanation:

Data

pOH = 5.9

a) [OH⁻] = ?

pOH measures the [OH⁻]

Formula

pOH = -log[OH⁻]

-Substitution

5.9 = -log[OH⁻]

[OH⁻] = antilog (-5.9)

-Result

[OH⁻] = 1.26 x 10⁻⁶ M

b) [H₃O⁺]

pH + pOH = 14

-Solve for pH

pH = 14 - pOH

-Substitution

pH = 14 - 5.9

-Result

pH = 8.1

-Calculate [H₃O⁺]

pH = -log[H₃O⁺]

-Substitution

8.1 = -log[H₃O⁺]

[H₃O⁺] = antilog(-8.1)

-Result

[H₃O⁺] = 7.9 x 10⁻⁹ M

c) This solution is alkaline because the pH is higher than 7.

Karo-lina-s [1.5K]4 years ago
5 0
The answer is A
A. Poh 5.9
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Phosphorous pentoxide, P2O5(s), is produced from the reaction between pure oxygen and pure phosphorous (P, solid). What is the v
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Answer:

4190.22 L = 4.19 m³.

Explanation:

  • For the balanced reaction:

<em>2P₂ + 5O₂ ⇄ 2P₂O₅. </em>

It is clear that 2 mol of P₂ react with <em>5 mol of O₂ </em>to produce <em>2 mol of P₂O₅.</em>

  • Firstly, we need to calculate the no. of moles of 6.92 kilograms of P₂O₅ produced through the reaction:

no. of moles of P₂O₅ = mass/molar mass = (6920 g)/(283.88 g/mol) = 24.38 mol.

  • Now, we can find the no. of moles of O₂ is needed to produce the proposed amount of P₂O₅:

<u><em>Using cross multiplication:</em></u>

5 mol of O₂ is needed to produce → 2 mol of P₂O₅, from stichiometry.

??? mol of O₂ is needed to produce → 24.38 mol of P₂O₅.

∴ The no. of moles of O₂ needed = (5 mol)(24.38 mol)/(2 mol) = 60.95 mol.

  • Finally, we can get the volume of oxygen using the general law of ideal gas:<em> PV = nRT.</em>

where, P is the pressure of the gas in atm (P = 606.1 mm Hg/760 = 0.8 atm).

V is the volume of the gas in L (V = ??? L).

n is the no. of moles of the gas in mol (n = 60.95 mol).

R is the general gas constant (R = 0.0821 L.atm/mol.K),

T is the temperature of the gas in K (396.90°C + 273 = 669.9 K).

∴ V of oxygen needed = nRT/P = (60.95 mol)(0.0821 L.atm/mol.K)(669.9 K)/(0.8 atm) = 4190.22 L/1000 = 4.19 m³.

3 0
3 years ago
A student is planning an investigation of an acid-base reaction. Which of the following is not an accepted method of monitoring
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Answer:

Conductivity meter

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An indicator is an organic compound that changes its colour depending on the pH of the solution.

Since neutralization reaction can only be monitored by monitoring the pH of the solution, a conductivity meter cannot be used to monitor the progress of a neutralization reaction since it does not monitor the change in pH of the system under study.

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Answer:

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Read 2 more answers
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