I suspect that the pressure of this change is constant therefore
The equation is used from the combined gas law. (When pressure is constant both P's will cancel out P/P = 1)
V/T = V/T
Initial Change
Initially we have 2L at 20 degress what temperature will be at 1L.
2/20 = 1/T
0.1 = 1/T
0.1T = 1
T = 1/0.1
T = 10 degress celsius.
Hope this helps if you won't be able to understand what is the combined gas law just tell me :).
Answer:
(5.4 x 10³) x (1.2 x 10⁷) = 6.48 x 10¹⁰
With correct significant figures, the answer would be 6.5 x 10¹⁰.
Complete Question
The complete question is shown on the first uploaded image
Answer:
At Equilibrium the number of moles of =0.0104
At Equilibrium the number of moles of =0.0052
Explanation:
The explanation is shown on the second uploaded image
Answer:
22.1 g
Explanation:
Step 1: Write the balanced equation for the combustion of acetylene
2 C₂H₂ + 5 O₂ ⇒ 4 CO₂ + 2 H₂O
Step 2: Calculate the moles corresponding to 75.0 g of CO₂
The molar mass of CO₂ is 44.01 g/mol.
75.0 g × 1 mol/44.01 g = 1.70 mol
Step 3: Calculate the moles of C₂H₂ required to produce 1.70 moles of CO₂
The molar ratio of C₂H₂ to CO₂ is 2:4. The moles of C₂H₂ required are 2/4 × 1.70 mol = 0.850 mol.
Step 4: Calculate the mass corresponding to 0.850 moles of C₂H₂
The molar mass of C₂H₂ is 26.04 g/mol.
0.850 mol × 26.04 g/mol = 22.1 g