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morpeh [17]
3 years ago
6

When a 16.50 g sample containing nickel and oxygen is analyzed, 5.87 g of nickel are found. What is the percent composition of t

his mineral?
Chemistry
1 answer:
Virty [35]3 years ago
5 0

Answer:

\%O=64.2\%\\\\\%Ni=35.8\%

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to tell that since the total mass is 16.50 g and 5.87 g correspond to nickel, then the mass of oxygen is:

m_O=16.50g-5.87g=10.63g

And therefore, the resulting percent composition turns out to be:

\%O=\frac{10.60}{16.50} *100\%=64.2\%\\\\\%Ni=\frac{5.87}{16.50} *100\%=35.8\%

Regards!

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If nitrogen-13 has a half life of 2.5 years, how much remains from a 100g sample after 7.5 years
Sonbull [250]

Answer:

12.50g

Explanation:

T½ = 2.5years

No = 100g

N = ?

Time (T) = 7.5 years

To solve this question, we'll have to find the disintegration constant λ first

T½ = In2 / λ

T½ = 0.693 / λ

λ = 0.693 / 2.5

λ = 0.2772

In(N/No) = -λt

N = No* e^-λt

N = 100 * e^-(0.2772*7.5)

N = 100*e^-2.079

N = 100 * 0.125

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Dafna1 [17]

Answer:

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Explanation:

Given data:

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Now we will put the values in formula.

Number of moles = 148.6 g/ 16 g/mol

Number of moles = 9.29 mol

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Answer:

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Explanation:

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