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3 years ago

A car covered 450km in 5 hours. find the speed in meters per second

Mathematics

2 answers:

saw5 [17]3 years ago

3 0

Step-by-step explanation:

Hey there!

Given;

Distance (d) = 450 km = 450*1000 = 450000 m

Time(t) = 5 hours = 5*60*60 = 18000s

Now;

Speed (s) = Distance (d) /Time(t)

Or, s = 450000/18000

Or, s = 25m/s.

Therefore, the speed is 25m/s.

Hope it helps!

Ksivusya [100]3 years ago

3 0

Answer:

The car has a velocity of 25 m/s.

Step-by-step explanation:

There are two ways to solve this problem.

First way :

450km = 450.000m

5h = 5x 3.600s =18.000s

v = s/t = 450.000 / 18.000 = 25m/s

Second way :

Velocity = speed/time = 450 / 5 = 90 km/h

90/3.6 = 25 m/s

Either way, the car has a velocity of 25 m/s.

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Unit 3, Lesson 7

aksik [14]

Answer:

Find the complete table in attached file.

Step-by-step explanation:

Find the Incomplete table in attached file

Given:

A car travels 55 miles per hour for 2 hours.

So the speed of the car 55 miles per hour is constant for 2 hours.

Using speed formula.

$Speed=\frac{distance}{time}$

Second row.

From the second row of the table $time = \frac{1}{2}=0.5\ sec$ and speed is constant $speed = 55\ mi/hr$ , so we need to find only distance.

$Speed=\frac{distance}{time}$

$55=\frac{distance}{0.5}$

$distance = 55\times 0.5$

$distance = 27.5\ mi$

Third row.

From the third row of the table $time =1\frac{1}{2}=\frac{3}{2} = 1.5\ sec$ and speed is constant $speed = 55\ mi/hr$ , so we need to find only distance.

$Speed=\frac{distance}{time}$

$55=\frac{distance}{1.5}$

$distance = 55\times 1.5$

$distance = 82.5\ mi$

Fourth row.

From the fourth row of the table $distance =110\ miles$ and speed is constant $speed = 55\ mi/hr$ , so we need to find time.

$Speed=\frac{distance}{time}$

$time=\frac{distance}{speed}$

$time=\frac{110}{55}$

$time = 2\ sec$

Therefore we complete the table from the above calculation.

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A car covered 450km in 5 hours. find the speed in meters per second​

A car covered 450km in 5 hours. find the speed in meters per second