An ionic bond is a bond which occurs when there is a
difference in the electronegativity of the atoms. One atom which has a stronger
electronegativity tends to steal the electron of the other less electronegative
atom hence making it more negative (anion), while the other becomes a cation.
So answer is:
<span>b. a cation and an anion</span>
Answer:
it's C
Explanation:
the equilibrium sytem will shift to remove more of what was removed
Explanation:
The pH of a solution can you be found by using the formula
![pH = - log [ { H_3O}^{+}]](https://tex.z-dn.net/?f=pH%20%3D%20-%20log%20%5B%20%7B%20H_3O%7D%5E%7B%2B%7D%5D)
Since we are finding the [H3O+] , substitute the value of the pH and find it's antilog
We have
![4.63 = - log[ { H_3O}^{+}] \\ [ { H_3O}^{+}] = {10}^{ - 4.63} \\ \\ = 2.344 \times {10}^{ - 5} mol {dm}^{ - 3}](https://tex.z-dn.net/?f=4.63%20%3D%20%20-%20%20log%5B%20%7B%20H_3O%7D%5E%7B%2B%7D%5D%20%5C%5C%20%5B%20%7B%20H_3O%7D%5E%7B%2B%7D%5D%20%20%20%3D%20%20%7B10%7D%5E%7B%20-%204.63%7D%20%20%5C%5C%20%20%20%5C%5C%20%20%3D%202.344%20%5Ctimes%20%20%7B10%7D%5E%7B%20-%205%7D%20mol%20%7Bdm%7D%5E%7B%20-%203%7D%20%20)
Hope this helps you
Answer:
Here's what I get
Explanation:
A plant extract is a mixture because it contains different substances: acetone or ethanol, chlorophylls A and B, carotene and xanthophylls.
It is homogeneous because it is a solution. There is only one phase: the liquid phase. You cannot see the pigments as separate phases.
You can separate the pigments by paper, thin layer, or column chromatography.
Many schools use paper chromatography, because paper is cheap.
As the mixture of pigments follows the solvent up the paper, they separate into different coloured bands according to their attractive forces to the cellulose in the paper.
The chlorophylls are strongly attracted to the paper, so they don't travel very far.
The nonpolar carotene molecules have little attraction to the polar cellulose, so they are carried along by the solvent front.
Answer:

Explanation:
From the question we are told that:
Pressure 
Temperature 
Volume 
Heat Produced 
Generally the equation for ideal gas is mathematically given by



Therefore


Since
Heat of combustion of Methane=889 kJ/mol
Heat of combustion of Propane=2220 kJ/mol
Therefore

Comparing Equation 1 and 2 and solving simultaneously




Therefore
Mole fraction 0f Methane is mathematically given as


