What will most likely happen when a component is removed from a reaction system at equilibrium?
1 answer:
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<span>Chemical reactions involving only liquids will be influenced by ALL of the following EXCEPT: </span><span><span>c) size of reactant particles d) pressure of the system.
</span>Reason:
1) As per Arrhenius theory, rate of chemical reactions is influence by temperature. Mathematically it is expressed as: k = A exp(-Ea/RT)
</span>where, k = rate constant, A = collision frequency, Ea = activation energy, T = temp. From above relation, it can be seen that, chemical reactions involving only liquids will be influenced temperature.
2) Also, if know that, rates of chemical reactions is mathematically expressed as:![Rate = [A]^{x} B^{y}....](https://tex.z-dn.net/?f=%20Rate%20%3D%20%5BA%5D%5E%7Bx%7D%20B%5E%7By%7D....%20%20)
,
where A, B, .. are the reactants.
From above relation, it can be seen that, chemical reactions involving only liquids will be influenced concentration i.e. number of particle.
3) However, since all the reactant and catalyst used (if any) is in liquid state, particle size of same will not influence the reaction.
4) Also, since there are no gas-phase reactant, pressure will not affect the reaction.
</span>Reason:
1) As per Arrhenius theory, rate of chemical reactions is influence by temperature. Mathematically it is expressed as: k = A exp(-Ea/RT)
</span>where, k = rate constant, A = collision frequency, Ea = activation energy, T = temp. From above relation, it can be seen that, chemical reactions involving only liquids will be influenced temperature.
2) Also, if know that, rates of chemical reactions is mathematically expressed as:
where A, B, .. are the reactants.
From above relation, it can be seen that, chemical reactions involving only liquids will be influenced concentration i.e. number of particle.
3) However, since all the reactant and catalyst used (if any) is in liquid state, particle size of same will not influence the reaction.
4) Also, since there are no gas-phase reactant, pressure will not affect the reaction.