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SpyIntel [72]
3 years ago
14

What will most likely happen when a component is removed from a reaction system at equilibrium?

Chemistry
1 answer:
Sever21 [200]3 years ago
8 0

Answer:

it's C

Explanation:

the equilibrium sytem will shift to remove more of what was removed

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A balloon occupies 175 cm at 25.0 C. What volume will it occupy at 42.5 °C?
patriot [66]

175 cm³ instead of 175 cm.

Answer:

297.5 cm³

Explanation:

From the question;

Initial volume; V1 = 175 cm³

Initial temperature; T1 = 25°C

Final temperature; T2 = 42.5°C

From Charles law we can find the volume V2 from the equation;

V1/T1 = V2/T2

Making V2 the subject gives;

V2 = V1 × T2/T1

V2 = (175 × 42.5)/25

V2 = 297.5 cm³

4 0
3 years ago
Can anyone do balance equation?
miss Akunina [59]
47)1-6 and 5&6-8 hope this helps!
3 0
3 years ago
Based on the molar masses, how can you tell that an equation is balanced?
Ilya [14]
When you work with molar mass, you solve for the quantity of ''Moles'' within the substance by converting Mass. The way you can tell the equation is balanced would be by knowing whether the moles were equivalent on both sides or not. Therefore, if they are equal, it is balanced considering you have the same amount of moles on each side of the equation.
7 0
3 years ago
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7. What must you do before you make a hypothesis?
almond37 [142]

Answer:

Ask a question?

Explanation:

look at the scientific method uwu

6 0
3 years ago
9. How many grams are in 2.0 x 105 molecules of carbon monoxide?
timama [110]

Answer: 9.3 x 10^ 18 g CO

Explanation:

Start by knowing that carbon monoxide is the compound CO. To convert molecules to grams, you first need to convert molecules to moles. This can be done using the conversion factor for Avogadro's Number:

(2.0 x 10^5 molecules CO) x 1 mol CO / 6.02 x 10^23 molecules CO

This cancels molecules CO.

Then, you can convert moles to grams, which is your desired quantity. You can find the number of grams for CO by looking at the periodic table and adding together their masses. C = 12 g and O = 16 g. Total of 28 g CO:

(1 mol CO) x 28 g CO / 1 mol CO

This cancels mol CO, which leaves grams CO.

5 0
3 years ago
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