Answer:
The velocity of the fish hitting the ground is , v = 45.795 m/s
Explanation:
Given data,
The mass of the fish, m = 5 kg
The height of the bird from the surface, h = 107 m
Using the III equation of motion,
v² = u² + 2gs
<em> v = √(u² + 2gs)</em>
Substituting the values,
v = √(0² + 2 x 9.8 x 107)
= 45.795 m/s
Hence, the velocity of the fish hitting the ground is, v = 45.795 m/s
█ Question <span>█
</span><span>How can long term alcohol abuse affect the liver?
</span>█ Answer <span>█
</span>
Cirrhosis is liver damage from people who do alcohol abuse. The liver will be affected this way. The answer is letter B.
<span>Hope that helps! ★ <span>If you have further questions about this question or need more help, feel free to comment below or leave me a PM. -UnicornFudge aka Nadia </span></span>
Answer:
A_resulting = 0.2 m
Explanation:
Let's analyze the impact of the pulse with the pole, this is a fixed obstacle that does not move therefore by the law of action and reluctant, the force that the pole applies on the rope is of equal magnitude to the force of the rope on the pole (pulse), but opposite directional, so the reflected pulse reverses its direction and sense.
With this information we analyze a point on the string where the incident pulse is and each reflected with an amplitude A = 0.1 m, the resulting is
A_res = 2A
A_resultant = 2 .01
A_resulting = 0.2 m
Answer:
Air resistance
Answer B is correct
Explanation:
The friction that occurs when air pushes against a moving object causing it to negatively accelerate is called as air resistance.
hope this helps
brainliest appreciated
good luck! have a nice day!
Explanation:
The given data is as follows.
Length of beam, (L) = 5.50 m
Weight of the beam, (
) = 332 N
Weight of the Suki, (
) = 505 N
After crossing the left support of the beam by the suki then at some overhang distance the beam starts o tip. And, this is the maximum distance we need to calculate. Therefore, at the left support we will set up the moment and equate it to zero.
= 0
x = 
= 
= 0.986 m
Hence, the suki can come (2 - 0.986) m = 1.014 from the end before the beam begins to tip.
Thus, we can conclude that suki can come 1.014 m close to the end before the beam begins to tip.
