1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
NemiM [27]
3 years ago
15

While an object is in projectile motion (with upward being positive) with no air resistance ct is in projectile motion (with upw

ard being positive) with no air resistance, Group of answer choices the horizontal component of its velocity remains constant and the vertical component of its acceleration is equal to -g. the vertical component of its velocity remains constant and the vertical component of its acceleration is equal to -g the horizontal component of its velocity remains constant and the horizontal component of its acceleration is equal to -g the horizontal component of its velocity remains constant and the vertical component of its acceleration is equal to zero. the vertical component of both its velocity and its acceleration remain constant.
Physics
1 answer:
andrew11 [14]3 years ago
3 0

Answer:

The horizontal component of its velocity remains constant and the vertical component of its acceleration is equal to -g.

Explanation:

This is because, the projectile has both vertical and horizontal components of velocity. But, its vertical component of velocity changes as the object moves whereas, its horizontal component of velocity remains constant.

Also, the projectile has only vertical component of acceleration and no horizontal component of acceleration since, its horizontal component of velocity remains constant. Thus, no change in the horizontal component of velocity.

The vertical component of acceleration is equal to -g since, the weight is the only vertical force acting on it.

So, <u>the horizontal component of its velocity remains constant and the vertical component of its acceleration is equal to -g.</u>

You might be interested in
A heat engine operates with 70.0 kcal of heat supplied and exhausts 30.0 kcal of heat. How much work did the engine do?
gladu [14]

The work done by the heat engine is 40 kCal.

The given parameters;

  • input heat of the engine, Q₁ = 70 kCal
  • output heat of the engine, Q₂ = 30 kCal

To find:

  • the work done by the heat engine

The work done by the heat engine is the change in the heat energy of the engine;

W = Q₂ - Q₁

Substitute the given parameters and solve work done (W)

W = 70 kCal - 30 kal

W = 40 kCal

Thus, the work done by the heat engine is 40 kCal.

Learn more here: brainly.com/question/4280097

4 0
3 years ago
Neurons in our bodies carry weak currents that produce detectable magnetic fields. A technique called magnetoencephalography, or
Stolb23 [73]

Answer:

I = (1.80 × 10⁻¹⁰) A

Explanation:

From Biot Savart's law, the magnetic field formula is given as

B = (μ₀I)/(2πr)

B = magnetic field = (1.0 × 10⁻¹⁵) T

μ₀ = magnetic constant = (4π × 10⁻⁷) H/m

r = 3.6 cm = 0.036 m

(1.0 × 10⁻¹⁵) = (4π × 10⁻⁷ × I)/(2π × 0.036)

4π × 10⁻⁷ × I = 1.0 × 10⁻¹⁵ × 2π × 0.036

I = (1.80 × 10⁻¹⁰) A

Hope this Helps!!!

3 0
4 years ago
What is the acceleration of a car that maintains a constant velocity of 100km/h for 10 s
Mademuasel [1]
A constant velocity means the acceleration is zero.
4 0
3 years ago
Read 2 more answers
Molly is jogging on the treadmill. After 20 minutes, her heart rate has not increased, she is able to talk, and she is not sweat
lakkis [162]
Molly could increase her heart rate by turning around and jogging backwards, by jogging on her hands instead of her feet, or by continuing to jog normally but increasing the speed of the treadmill.
3 0
3 years ago
Read 2 more answers
In the Bohr’s model of the hydrogen atom, the electron moves in a circular orbit of radius 5.041 × 10−11 m around the proton. As
Ilia_Sergeevich [38]

Answer:

The orbital speed of the electron is 2.296 x 10⁶ m/s

Explanation:

Given;

radius of the circular orbit, r = 5.041 × 10⁻¹¹ m

In the Bohr’s model of the hydrogen atom, the velocity of the electron is given as;

V = \frac{nh}{2\pi mr}

where;

h is Planck's constant

m is mass of electron

r is the radius of the circular orbit

n is the energy level of hydrogen in ground state

Substitute in these values and solve for V

V = \frac{nh}{2\pi mr} = \frac{1*6.626*10^{-34}}{2\pi *9.11 *10^{-31}*5.041*10^{-11}}\\\\V = 2.296*10^6  \ m/s

Therefore, the orbital speed of the electron is 2.296 x 10⁶ m/s

4 0
4 years ago
Other questions:
  • Two blocks of masses mA and mB are connected by a massless spring. The blocks are moved apart, stretching the spring, and subseq
    10·1 answer
  • What scientific device fascinated Newton as a Boy?
    11·1 answer
  • As a bat flies toward a wall at a speed of 6.0 m/s, the bat emits an ultrasonic sound wave with frequency 30.0 kHz. What frequen
    13·1 answer
  • Question 1(Multiple Choice Worth 4 points) The star named Canopus has a declination of approximately –52°. Which of these statem
    14·1 answer
  • Why are you more likely to get a concussion when hit by a field hockey ball than a
    7·1 answer
  • Sally stands 3 meters from the fulcrum. Reggie weighs 800 N and stands 2 meters from the fulcrum. The see saw is balanced. How m
    6·1 answer
  • The speed of an electromagnetic wave is a constant, 3.0 × 10 8m/s. The wavelength of a wave is 0.6 meters.
    11·2 answers
  • Honeybees acquire a positive charge while flying through the air. The rapid motion of the wings through the air provides the "fr
    9·1 answer
  • The mass of an object on earth is 20 kg what will be the mass of that object on moon? And why? ​
    10·1 answer
  • Five different forces act on an object. Is it possible for the net force on the object to be zero? Explain
    12·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!