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Sonbull [250]
3 years ago
13

When you push a 1.85-kg book resting on a

Physics
1 answer:
Margaret [11]3 years ago
6 0

Answer:

Given:

mb=2.05 kgmb=2.05 kg Mass of the book

fs=2.45 Nfs=2.45 N Static friction

fk=1.50 Nfk=1.50 N Kinetic friction

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What is the energy (in electron volts) of a 50 ghz (1 gigahertz = 109 hz) microwave photon?
KIM [24]
The frequency of the microwave photon is:
f=50 GHz=50 \cdot 10^9 Hz
and its energy is given by:
E=hf
where 
h=6.6 \cdot 10^{-34}Js is the Planck constant
f is the photon frequency

By substituting the numbers into the formula, we find the photon's energy:
E=hf=(6.6 \cdot 10^{-34}Js)(50 \cdot 10^9 Hz)=3.3 \cdot 10^{-23}J

Now we want to convert it into electronvolts (eV). We know that
1 eV= 1.6 \cdot 10^{-19}J
Therefore, we should simply divide our energy by this conversion factor, and we get:
E= \frac{3.3 \cdot 10^{-23} J}{1.6 \cdot 10^{-19} J/eV}=2.1 \cdot 10^{-4}eV
8 0
3 years ago
A 8.1 kg object initially at rest is pushed down a 15.0 m tall hill. What is the speed of the object at the bottom of the hill?
topjm [15]

Answer:

The velocity of the object at the bottom is, v = 17.15 m/s

Explanation:

Given data,

The initial velocity of the object, u = 0

The height of the hill, h = 15 m

Let 'S' be the distance of the slope of the hill and 'Ф' be the slope of the hill formed with the ground.

The acceleration due to gravity component along the slope is given by,

                                      a = g Sin Ф

The distance of the slope since height 'h' of the hill is given,

                                       s = h / Sin Ф

Using the III equation of motion,

                                      v² = 2 as                    (∵ u = 0)

                                      v² = 2 x g Sin Ф x h / Sin Ф

                                           = 2 gh

Therefore,

                                      <em> v = √(2gh)</em>

Substituting the given values,

                                       v = √(2x9.8x15)

                                          = 17.15 m/s

Hence, the velocity of the object at the bottom is, v = 17.15 m/s

8 0
4 years ago
A hollow spherical shell has mass 8.05kg and radius 0.215m . It is initially at rest and then rotates about a stationary axis th
hram777 [196]

Answer: The kinetic energy of the shell after it has turned through 5.25rev is 7.32J

Explanation: Please see the attachments below

4 0
3 years ago
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Can you change your mass without changing your weight?
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No, because mass is the amount of matter in something and weight is the pull of gravity on a object, for example you would weigh 65 pounds.. and have the mass of 1058..if you were in space your weight would change but your mass will always stay the same
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What can scientist learn from studying sedimentary rocks?
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They are made of rocks
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