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Strike441 [17]
3 years ago
13

Please help me please it's urgent​

Chemistry
1 answer:
alisha [4.7K]3 years ago
3 0

Answer:

<h2>Paraphrase this! I got this online!</h2>

1.A a Chemical Reaction is a process that involves rearrangement of the molecular or ionic structure of a substance, as opposed to a change in physical form or a nuclear reaction.

1.A Chemical reactions involve breaking chemical bonds between reactant molecules (particles) and forming new bonds between atoms in product particles (molecules)

1A.Chemical bonding, any of the interactions that account for the association of atoms into molecules, ions, crystals, and other stable species that make up the familiar substances of the everyday world.

2a.A gas evolution reaction is a chemical reaction in which one of the end products is a gas such as oxygen or carbon dioxide. Gas evolution reactions may be carried out in a fume chamber when the gases produced are poisonous when inhaled or explosive.

2b.a color change is usually an indicator that a reaction is occurring

2c.Processes involved in changes of state include melting, freezing, sublimation, deposition, condensation, and evaporation

3A.When you increase the pressure, the molecules have less space in which they can move. That greater density of molecules increases the number of collisions

3B.As an object gets hot, its atoms and molecules vibrate. As they vibrate, they release energy in the form of light. ... In chemiluminescence, energy from a chemical reaction excites the electrons of a substance

3C. Catalysis is the process of increasing the rate of a chemical reaction by adding a substance known as a catalyst. Catalysts are not consumed in the reaction and remain unchanged after it.

3D.Most chemical reactions involve the breaking and formation of chemical bonds. It takes energy to break a chemical bond but energy is released when chemical bonds are formed. If more energy is released than consumed, then the chemical reaction evolves heat and is said to be exothermic. ... Most reactions are exothermic.

<h2>Paraphrase this! I got this online!</h2><h2>Paraphrase this! I got this online!</h2><h2>Paraphrase this! I got this online!</h2>
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Answer: The molecular formula for androstenedione is, C_{19}H_{26}O_2

Explanation:

The chemical equation for the combustion of hydrocarbon having carbon, hydrogen and oxygen follows:

C_xH_yO_z+O_2\rightarrow CO_2+H_2O

where, 'x', 'y' and 'z' are the subscripts of Carbon, hydrogen and oxygen respectively.

We are given:

Mass of CO_2=5.527g

Mass of H_2O=1.548g

We know that:

Molar mass of carbon dioxide = 44 g/mol

Molar mass of water = 18 g/mol

For calculating the mass of carbon:

In 44 g of carbon dioxide, 12 g of carbon is contained.

So, in 5.527 g of carbon dioxide, \frac{12}{44}\times 5.527=1.507g of carbon will be contained.

For calculating the mass of hydrogen:

In 18 g of water, 2 g of hydrogen is contained.

So, in 1.548 g of water, \frac{2}{18}\times 1.548=0.172g of hydrogen will be contained.

For calculating the mass of oxygen:

Mass of oxygen in the compound = (1.893g)-[(1.507g)+(0.172g)]=0.214g

To formulate the empirical formula, we need to follow some steps:

Step 1: Converting the given masses into moles.

Moles of Carbon =\frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{1.507g}{12g/mole}=0.126moles

Moles of Hydrogen = \frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{0.172g}{1g/mole}=0.172moles

Moles of Oxygen = \frac{\text{Given mass of oxygen}}{\text{Molar mass of oxygen}}=\frac{0.214g}{16g/mole}=0.0133moles

Step 2: Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 0.0133 moles.

For Carbon = \frac{0.126}{0.0133}=9.5

For Hydrogen  = \frac{0.172}{0.0133}=12.9\approx 13

For Oxygen  = \frac{0.0133}{0.0133}=1

Step 3: Taking the mole ratio as their subscripts.

The ratio of C : H : O = 9.5 : 13 : 1

To make in a whole number we are multiplying the ratio by 2, we get:

The ratio of C : H : O = 19 : 26 : 2

Thus, the empirical formula for the given compound is C_{19}H_{26}O_2

The empirical formula weight of C_{19}H_{26}O_2 = 19(12) + 26(1) + 2(16) = 286 gram/eq

Now we have to calculate the molecular formula of the compound.

Formula used :

n=\frac{\text{Molecular formula}}{\text{Empirical formula weight}}

n=\frac{286.4}{286}=1

Molecular formula = C_{19}H_{26}O_2

Therefore, the molecular formula for androstenedione is, C_{19}H_{26}O_2

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