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marin [14]
3 years ago
5

A 100 kg bag of sand has a weight on 100 N. When dropped its acceleration is what?

Physics
1 answer:
Anettt [7]3 years ago
4 0

Answer:

The acceleration of the bag of sand is 1\ m/s^2.

Explanation:

We have,

Mass of a bag of sand is 100 kg

Weight of the bag of sand is 100 N

It is required to find the acceleration of the bag when it is dropped. The weight of an object is given by :

F =ma

When it is dropped, a = g

g=\dfrac{F}{m}\\\\g=\dfrac{100}{100}\\\\g=1\ m/s^2

So, the acceleration of the bag of sand is 1\ m/s^2.

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What are the three ways of answering a scientific question
My name is Ann [436]

Answer:

Let's start by understanding what exactly a scientific question is. A scientific question is a question that may lead to a hypothesis and help us in answering (or figuring out) the reason for some observation. A good scientific question has certain characteristics. It should have some answers (real answers), should be testable.

Here's examples of a few:

Why is that a star?

or

What is that star made of?

Hope this can lead you to the answer you're looking for at least!!

5 0
3 years ago
Noah stands 170 meters away from a steep canyon wall. He shouts and hears the echo of his
bezimeni [28]
340 ms


I got it right and I hope you do as well
6 0
3 years ago
A rifle has a mass of 7-kg and the bullet has a mass of 0.7-kg. If the velocity of the bullet is 350-m/s after the rifle is fire
nevsk [136]

Answer:

-35 m/s

Explanation:

Momentum is conserved.

Momentum before firing = momentum after firing

m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂

Before the bullet is fired, the bullet and rifle have no velocity, so u₁ and u₂ are 0.

0 = m₁v₁ + m₂v₂

Given m₁ = 0.7 kg, v₁ = 350 m/s, and m₂ = 7 kg:

0 = (0.7 kg) (350 m/s) + (7 kg) v

v = -35 m/s

The rifle recoils at 35 m/s in the opposite direction.

8 0
3 years ago
Suppose that a meter stick is balanced at its center.  A 0.24 kg mass is then positioned at the 6-cm mark.   At what cm mark mus
Scilla [17]

Answer:

80.17 cm

Explanation:

Taking moments of forces about the center, the total clockwise moments is equal to the total counter clockwise moment:

Force * distance (counter clockwise) = force * distance (clockwise)

0.24 * 9.8 * (50 - 6) = 0.35 * 9.8 * (x - 50)

0.24 * 44 = 3.43x - 171.5

103.5 = 3.43x - 171.5

=> 3.43x = 103.5 + 171.5

3.43x = 275

x = 275/3.43 = 80.17 cm

8 0
3 years ago
Convert the polar representation of this complex number into its standard form: z=6(cos300 isin300
sergey [27]
<span>3-3√3i is the answer my friend </span>
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3 years ago
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