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Helen [10]
3 years ago
12

The equilibrium-constant expression is used to describe the concentration of reactants and products for a reaction in dynamic eq

uilibrium. For ideal gases and ideal solutions in homogeneous equilibria, where all reactants and products are in the same phase, the extent to which a particular chemical reaction proceeds to products is given by the equilibrium equation.
aA+bB⇌cC+dD , K=[C]c[D]d[A]a[B]b

where K is the equilibrium constant and the right-hand side of the equation is known as the equilibrium-constant expression.

The concentration of each product raised to its coefficient is divided by the concentration of each reagent raised to its coefficient according the the balanced chemical equation. Therefore, the higher the concentration of products, the larger the value of K will be.

Required:
Identify the proper form of the equilibrium-constant expression for the equation.
N2(g)+O2(g)⇌2NO(g)
Chemistry
1 answer:
Lunna [17]3 years ago
8 0

Answer: K=\frac{[NO]^2}{[N_2]^1[O_2]^1}

Explanation:

Equilibrium constant is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as K

For the given chemical reaction:

N_2(g)+O_2(g)\rightleftharpoons 2NO(g)

The expression for K is written as:

K=\frac{[NO]^2}{[N_2]^1[O_2]^1}

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natima [27]
I believe the correct answer from the choices listed above is the last option. The attractive force that occurs <span>between the sun and the earth is called gravity. Hope this answers the question. Have a nice day. Feel free to ask more questions.</span>
3 0
3 years ago
Read 2 more answers
1. What % of the nation's energy is used by the Industrial<br> Sector?
kari74 [83]

Answer:

Petroleum:92 Percent

Natural Gas:3 Percent

Renewable energy:5 Percent

Explanation:

US primary energy consumption by source and sector (2017)[17]

Supply sources Percent of source Demand sectors Percent of sector

Petroleum

36.2% 72% Transportation

23% Industrial

5% Residential and commercial

1% Electric power Transportation

28.1% 92% Petroleum

3% Natural gas

5% Renewable energy

Natural gas

28.0% 3% Transportation

35% Industrial

28% Residential and commercial

34% Electric power Industrial

21.9% 38% Petroleum

45% Natural gas

5% Coal

12% Renewable energy

Coal

13.9% 9% Industrial

<1% Residential and commercial

91% Electric power Residential and commercial

10.4% 16% Petroleum

76% Natural gas

<1% Coal

8% Renewable energy

Renewable energy

11.0% 13% Transportation

23% Industrial

7% Residential and commercial

57% Electric power Electric power

37.2% 1% Petroleum

26% Natural gas

34% Coal

17% Renewable energy

23% Nuclear electric power

Nuclear electric power

8.4% 100% Electric power  

3 0
3 years ago
Which of these is the smallest volume 500mL, 2,500 cm3, 5.5•10-1, 25 m3
mezya [45]
25m³.
500mL = 500cm³
25m³ = 2,500cm³
5.5x9 = 49.5(cm³)
25m³ is the smallest among the others.
5 0
3 years ago
The atomic masses of 151eu and 153eu are 150.919860 and 152.921243 amu, respectively. The average atomic mass of europium is 151
vitfil [10]

Answer:-  The natural abundance of ^1^5^1_E_u is 0.478 or 47.8% and ^1^5^3_E_u is 0.522 or 52.2% .

Solution:- Average atomic mass of an element is calculated from the atomic masses of it's isotopes and their abundances using the formula:

Average atomic mass = mass of first isotope(abundance) + mass of second isotope(abundance)

We have been given with atomic masses for ^1^5^1_E_u and ^1^5^3_E_u as 150.919860 and 152.921243 amu, respectively.  Average atomic mass of Eu is 151.964 amu.

Sum of natural abundances of isotopes of an element is always 1. If we assume the abundance of ^1^5^1_E_u as n then the abundance of ^1^5^3_E_u would be 1-n .

Let's plug in the values in the formula:

151.964=150.919860(n)+152.921243(1-n)

151.964=150.919860n+152.921243-152.921243n

on keeping similar terms on same side:

151.964-152.921243=150.919860n-152.921243n

-0.957243=-2.001383n

negative sign is on both sides so it is canceled:

0.957243=2.001383n

n=\frac{0.957243}{2.001383}

n=0.478

The abundance of ^1^5^1_E_u is 0.478 which is 47.8%.  

The abundance of ^1^5^3_E_u is = 1-0.478

= 0.522 which is 52.2%

Hence, the natural abundance of ^1^5^1_E_u is 0.478 or 47.8% and ^1^5^3_E_u is 0.522 or 52.2% .


3 0
3 years ago
I can distunguish between elements, compounds and mixtures.
FinnZ [79.3K]

Answer: The answer is element

Hope this helps  and please brainliest and ty

7 0
3 years ago
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