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Helen [10]
3 years ago
12

The equilibrium-constant expression is used to describe the concentration of reactants and products for a reaction in dynamic eq

uilibrium. For ideal gases and ideal solutions in homogeneous equilibria, where all reactants and products are in the same phase, the extent to which a particular chemical reaction proceeds to products is given by the equilibrium equation.
aA+bB⇌cC+dD , K=[C]c[D]d[A]a[B]b

where K is the equilibrium constant and the right-hand side of the equation is known as the equilibrium-constant expression.

The concentration of each product raised to its coefficient is divided by the concentration of each reagent raised to its coefficient according the the balanced chemical equation. Therefore, the higher the concentration of products, the larger the value of K will be.

Required:
Identify the proper form of the equilibrium-constant expression for the equation.
N2(g)+O2(g)⇌2NO(g)
Chemistry
1 answer:
Lunna [17]3 years ago
8 0

Answer: K=\frac{[NO]^2}{[N_2]^1[O_2]^1}

Explanation:

Equilibrium constant is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as K

For the given chemical reaction:

N_2(g)+O_2(g)\rightleftharpoons 2NO(g)

The expression for K is written as:

K=\frac{[NO]^2}{[N_2]^1[O_2]^1}

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a question that can be answered wity a hypothesis is a question a scientist can answer

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50 Points for whoever does it and shows their work. Maya has four glasses of milk. The temperature and the amount of milk in eac
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A. 20 grams of milk at 10°C

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Alex dragged a log across the yard in 30 the log weighted 400n she did 900 j of work how much power did I she have
In-s [12.5K]

The power used by Alex to drag the log across the yard is determined as 2,656 W.

<h3>Mass of the log</h3>

The mass of the log is calculated as follows;

W = mg

m = W/g

m = (400)/9.8

m = 40.82 kg

<h3>Velocity of the log</h3>

K.E = ¹/₂mv²

v² = 2K.E/m

v² = (2 x 900)/(40.82)

v² = 44.096

v = 6.64 m/s

<h3>Power used by Alex</h3>

P = Fv

P = 400 x 6.64

P = 2,656 W

Learn more about power here: brainly.com/question/13881533

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2 years ago
Please help!! I was sick when he went over this
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Answer:

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Explanation:

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3 years ago
Calculate the work, w, gained or lost by the system when a gas expands from 15 L to 45 L against a constant external pressure of
marta [7]

Answer:

Work done by the system = 4545 J

Explanation:

The expression for the calculation of work done is shown below as:

w=-P\times \Delta V

Where, P is the pressure

\Delta V is the change in volume

From the question,  

\Delta V = 45 - 15 L = 30 L

P = 1.5 atm

w=-1.5\times 30\ atmL

Also, 1 atmL = 101 J

So,  

w=-1.0\times0.75\times 101\ J=-4545\ J (negative sign implies work is done by the system)

<u>Work done by the system = 4545 J</u>

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3 years ago
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