<u>Answer:</u>
<u>For a:</u> The number of moles of KI are and mass is
<u>For b:</u> The number of moles of sulfuric acid are and mass is
<u>For c:</u> The number of moles of potassium chromate are and mass is 5.51 g.
<u>For d:</u> The number of moles of ammonium sulfate are 39.018 moles and mass is 5155.84 grams.
<u>Explanation:</u>
To calculate the molarity of solution, we use the equation:
.....(1)
To calculate the number of moles of a substance, we use the equation:
.....(2)
- <u>For a:</u>
Molarity of KI =
Volume of solution = 325 mL = 0.325 L (Conversion factor: 1 L = 1000 mL)
Putting values in equation 1, we get:
Now, using equation 2, we get:
Moles of KI =
Molar mass of KI = 166 g/mol
Putting values in equation 2, we get:
Hence, the number of moles of KI are and mass is
- <u>For b:</u>
Molarity of sulfuric acid =
Volume of solution = 75 mL = 0.075 L
Putting values in equation 1, we get:
Now, using equation 2, we get:
Moles of sulfuric acid =
Molar mass of sulfuric acid = 98 g/mol
Putting values in equation 2, we get:
Hence, the number of moles of sulfuric acid are and mass is
- <u>For c:</u>
Molarity of potassium chromate =
Volume of solution = 0.250 L
Putting values in equation 1, we get:
Now, using equation 2, we get:
Moles of potassium chromate =
Molar mass of potassium chromate = 194.2 g/mol
Putting values in equation 2, we get:
Hence, the number of moles of potassium chromate are and mass is 5.51 g.
- <u>For d:</u>
Molarity of ammonium sulfate = 3.716 M
Volume of solution = 10.5 L
Putting values in equation 1, we get:
Now, using equation 2, we get:
Moles of ammonium sulfate = 39.018 mol
Molar mass of ammonium sulfate = 132.14 g/mol
Putting values in equation 2, we get:
Hence, the number of moles of ammonium sulfate are 39.018 moles and mass is 5155.84 grams.