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Setler [38]
2 years ago
9

All of the following statements about different elements are true EXCEPT: Group of answer choices Krypton is one of the noble ga

ses. Manganese is a transition metal. Sulfur is considered a metalloid. Iodine is a halogen. Barium is an alkaline earth metal.
Chemistry
1 answer:
seropon [69]2 years ago
3 0

Sulfur is an element of the periodic table that is not considered a metalloid.

<h3>What is sulfur?</h3>

Sulfur is a chemical element of the periodic table that has the following characteristics:

  • Atomic number 16
  • S symbol
  • Sulfur is classified as a nonmetal
  • It has a yellow color

<h3>What are metalloids?</h3>

Metalloids are a set of chemical elements of the periodic table that are characterized by having an intermediate behavior between metals and non-metals, in terms of ionization energies and binding properties.

It is not easy to distinguish them from true metals. They conduct electrical current better than non-metals, but they are not good conductors like metals. In addition, they are usually very varied in their shape and coloration.

The list of metalloids includes the following elements:

  • Boron (B)
  • Silicon (Si)
  • Germanium (Ge)
  • Arsenic (As)
  • Antimony (Sb)
  • Tellurium (Te)
  • Polonium (Po)

Learn more about periodic table in: brainly.com/question/11155928

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A solution was prepared by mixing 0.5000 m hno2 with 0.380 m no2-. ka = 4.58 x 10-4. calculate the ph of the solution. show work
adell [148]

pH of buffer can be calculated as:

pH=pKa+log[salt]/[Acid]

As ka = 4.58 x 10-4

Concentration of [Salt] that is NO2(-1)=0.380M

Concentration of [Acid] that is HNO2=0.500M

So, pH= -log(4.58*10^-4)+log((0.380)/0.500))

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So pH of solution will be 3.21

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2 years ago
The British gold sovereign coin is an alloy of gold and copper having a total mass of 7.988 g, and is 22-karat gold.
azamat

Answer:

(a) m_{gold}=7.322g

(b)

V_{gold}=0.379cm^3

V_{copper}=0.122cm^3

(c) \rho _{coin}=15.94g/cm^3

Explanation:

Hello,

(a) In this case, with the given formula we easily compute the mass of gold contained in the sovereign  as shown below:

m_{gold}=\frac{m_{tota}*karats}{24}=\frac{7.988g*22}{24}=7.322g

(b) Now, by knowing the density of gold and copper, 19.32 and 8.94 g/cm³ respectively, we compute each volume, by also knowing that the rest of the coin contains copper:

V_{gold}=\frac{m_{gold}}{\rho_{gold}} =\frac{7.322g}{19.32g/cm^3}=0.379cm^3

m_{copper}=7.988g-7.322g=1.09g\\V_{copper}=\frac{m_{copper}}{\rho_{copper}}=\frac{1.09g}{8.94g/cm^3}  \\\\V_{copper}=0.122cm^3

(c) Finally, the volume is computed by dividing the total mass over the total volume containing both gold and copper:

\rho _{coin}=\frac{m_{total}}{V_{gold}+V_{copper}}=\frac{7.988 g}{0.379cm^3+0.122cm^3}\\  \\\rho _{coin}=15.94g/cm^3

Best regards.

3 0
3 years ago
Read 2 more answers
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