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Setler [38]
2 years ago
9

All of the following statements about different elements are true EXCEPT: Group of answer choices Krypton is one of the noble ga

ses. Manganese is a transition metal. Sulfur is considered a metalloid. Iodine is a halogen. Barium is an alkaline earth metal.
Chemistry
1 answer:
seropon [69]2 years ago
3 0

Sulfur is an element of the periodic table that is not considered a metalloid.

<h3>What is sulfur?</h3>

Sulfur is a chemical element of the periodic table that has the following characteristics:

  • Atomic number 16
  • S symbol
  • Sulfur is classified as a nonmetal
  • It has a yellow color

<h3>What are metalloids?</h3>

Metalloids are a set of chemical elements of the periodic table that are characterized by having an intermediate behavior between metals and non-metals, in terms of ionization energies and binding properties.

It is not easy to distinguish them from true metals. They conduct electrical current better than non-metals, but they are not good conductors like metals. In addition, they are usually very varied in their shape and coloration.

The list of metalloids includes the following elements:

  • Boron (B)
  • Silicon (Si)
  • Germanium (Ge)
  • Arsenic (As)
  • Antimony (Sb)
  • Tellurium (Te)
  • Polonium (Po)

Learn more about periodic table in: brainly.com/question/11155928

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The Michaelis constant for pancreatic lipase is 5 mM. At 60 C, lipase is subject to deactivation with a half-life of 8 min. Fat
Dmitriy789 [7]

Explanation:

According to the given data, we will calculate the following.

 Half life of lipase t_{1/2} = 8 min x 60 s/min

                                       = 480 s

Rate constant for first order reaction is as follows.

         k_{d} = \frac{0.6932}{480}

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Rate of hydrolysis V_m_{o} = 0.07 mmol/L/s

Conversion X = 0.80

Final concentration (S) = S_{o} (1 - X)

                                      = 45 (1 - 0.80)

                                      = 9 mol/m^{3}

or,                                  = 9 mmol/L

It is given that K_{m} = 5mmol/L

Therefore, time taken will be calculated as follows.

                    t = -\frac{1}{K_{d}}ln[1 - \frac{K_{d}}{V}{K_{M} ln (\frac{S_{o}}{S}) + (S_{o} - S)]

Now, putting the given values into the above formula as follows.

            t = -\frac{1}{K_{d}}ln[1 - \frac{K_{d}}{V}{K_{M} ln (\frac{S_{o}}{S}) + (S_{o} - S)]  

             = -\frac{1}{1.44 \times 10^{-3}s^{-1}}ln[1 - \frac{1.44 \times 10^{-3}s^{-1}}{0.07 mmol/L/s&#10;}{K_{M} ln (\frac{45 mmol/L&#10;}{9 mmol/L&#10;}) + (45 mmol/L - 9 mmol/L&#10;)]

              = 1642.83 s \times \frac{1 min}{60 sec}

              = 27.38 min

Therefore, we can conclude that time taken by the enzyme to hydrolyse 80% of the fat present is 27.38 min.

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