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Vera_Pavlovna [14]
3 years ago
5

Help pls I have more ​

Mathematics
2 answers:
IgorC [24]3 years ago
7 0

Answer:

\frac{5}{10}  \times  \frac{2}{1}  =  \frac{10}{10}  = 1

\frac{1}{10}  \times  \frac{8}{3}  =  \frac{8}{30}  =  \frac{4}{15}

\frac{2}{6}  \times  \frac{12}{6}  =  \frac{24}{36}  =  \frac{2}{3}

\frac{1}{4}  \times  \frac{1}{3}  =  \frac{1}{12}

\frac{1}{5}  \times  \frac{1}{1}  =  \frac{1}{5}

earnstyle [38]3 years ago
3 0

Answer:

Step-by-step explanation:

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Write 0.0002507 in scientific notation.
Serggg [28]

Answer:

2.507* 10^-4

Step-by-step explanation:

0.0002507

We need to have one number to the left of the decimal

We move the decimal 4 places to the right

Since we moved the decimal to the right, the exponent on the power of 10 is negative

2.507* 10^-4

7 0
3 years ago
Write the slope-intercept form of the equation of the line described. through (2, -5) perpendicular to y = 1/3x -1
Cloud [144]

Answer:

y = -3x + 1

Step-by-step explanation:

Perpendicular lines have opposite reciprocal slopes, so the slope will be -3.

Plug in the slope and given point into y = mx + b

y = mx + b

-5 = -3(2) + b

-5 = -6 + b

1 = b

Then, plug in the slope and y intercept into y = mx + b again:

y = -3x + 1 will be the equation of the line

7 0
2 years ago
The expression 1/2bh gives the area of a triangle with a base length of b and a height of h.
alexandr402 [8]
I think the answer is B
8 0
3 years ago
Kenji earned the test scores below in English class
Tatiana [17]

The mean is 87 and median is 86.

<h3>What is mean and median?</h3>

The arithmetic mean is found by adding the numbers and dividing the sum by the number of numbers in the list.

The median is the middle value in a list ordered from smallest to largest.

Given:

79, 91, 93, 85, 86, and 88

So,

79+85+86+88+91+93/6 = 87

and, the median

79, 85, 86, 88, 91, 93

median = 86

Learn more about this concept here:

brainly.com/question/1863752

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2 years ago
Solve.<br><br> 16 + 40 ÷ 4 + (11 - 7)2
Kipish [7]
The answer to this is 34
7 0
3 years ago
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