All categories

3 years ago

Help pls I have more

Mathematics

2 answers:

IgorC [24]3 years ago

7 0

Answer:

$\frac{5}{10} \times \frac{2}{1} = \frac{10}{10} = 1$

$\frac{1}{10} \times \frac{8}{3} = \frac{8}{30} = \frac{4}{15}$

$\frac{2}{6} \times \frac{12}{6} = \frac{24}{36} = \frac{2}{3}$

$\frac{1}{4} \times \frac{1}{3} = \frac{1}{12}$

$\frac{1}{5} \times \frac{1}{1} = \frac{1}{5}$

earnstyle [38]3 years ago

3 0

Answer:

Step-by-step explanation:

You might be interested in

What is the answer for 16% of 150

liubo4ka [24]

Make an equation: x= 16% x 50 x= 16 50 ---- x ---- Cross Multiply 100 1 x= 16 ------ = 8

3 0

3 years ago

Read 2 more answers

Solve the equation.

Ad libitum [116K]

Answer:

D. 13 1/2

Step-by-step explanation:

2/3 x -2 = 7

2/3 x -2 + 2 = 7 + 2

2/3 x = 9

x = 9 (3/2)

x = 27/2

x = 13 1/2

6 0

3 years ago

Yi and Sue play a game. They start with the number 42000. Yi divides by a prime number, then passes the quotient to Sue. Then Su

andrew11 [14]

Whoever goes first will lose, that's the solution

6 0

3 years ago

Which of these statements is true for f(x)=(1/10)^x

lana66690 [7]

Step-by-step explanation:

Considering the function

$f\left(x\right)=\:\left(\frac{1}{10}\right)^x$

Analyzing option A)

Considering the function

$f\left(x\right)=\:\left(\frac{1}{10}\right)^x$

Putting $x = 1$ in the function

$f\left(1\right)=\:\left(\frac{1}{10}\right)^1$

$f\left(1\right)=\:\left\frac{1}{10}\right$

So, it is TRUE that when $x = 1$ then the out put will be $f\left(1\right)=\:\left\frac{1}{10}\right$

Therefore, the statement that '' The graph contains $\left(1,\:\frac{1}{10}\right)$ '' is TRUE.

Analyzing option B)

Considering the function

$f\left(x\right)=\:\left(\frac{1}{10}\right)^x$

The range of the function is the set of values of the dependent variable for which a function is defined.

$\mathrm{The\:range\:of\:an\:exponential\:function\:of\:the\:form}\:c\cdot \:n^{ax+b}+k\:\mathrm{is}\:\:f\left(x\right)>k$

$k=0$

$f\left(x\right)>0$

Thus,

$\mathrm{Range\:of\:}\left(\frac{1}{10}\right)^x:\quad \begin{bmatrix}\mathrm{Solution:}\:&\:f\left(x\right)>0\:\\ \:\mathrm{Interval\:Notation:}&\:\left(0,\:\infty \:\right)\end{bmatrix}$

Therefore, the statement that ''The range of $f(x)$ is $y > \frac{1}{10}$ " is FALSE

Analyzing option C)

Considering the function

$f\left(x\right)=\:\left(\frac{1}{10}\right)^x$

The domain of the function is the set of input values which the function is real and defined.

As the function has no undefined points nor domain constraints.

So, the domain is $-\infty \:$

Thus,

$\mathrm{Domain\:of\:}\:\left(\frac{1}{10}\right)^x\::\quad \begin{bmatrix}\mathrm{Solution:}\:&\:-\infty \:$

Therefore, the statement that ''The domain of $f(x)$ is $x>0$ '' is FALSE.

Analyzing option D)

Considering the function

$f\left(x\right)=\:\left(\frac{1}{10}\right)^x$

As the base of the exponential function is less then 1.

i.e. 0 < b < 1

Thus, the function is decreasing

Also check the graph of the function below, which shows that the function is decreasing.

Therefore, the statement '' It is always increasing '' is FALSE.

Keywords: function, exponential function, increasing function, decreasing function, domain, range

Learn more about exponential function from brainly.com/question/13657083

#learnwithBrainly

3 0

4 years ago

Read 2 more answers

An investment firm wants to create a billboard that displays an enlarged $1,000,000 bill. The actual size of the bill is 2.61 in

Mandarinka [93]

We know how wide the billboard will be. Therefore, to know how much the original image should be enlarged, you must divide the final width of the billboard between the current width of the invoice.

We know both data, then we perform the operation:

48 feet /6.14 inches = 7.81 feet / inches .

Therefore the correct answer is option D. 1″ = 7.81′

For the bill to cover the billboard, the bill must be expanded by a factor of 7.81 feet long per inch long that has the original image.

3 0

3 years ago

Help pls I have more ​

Help pls I have more