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Vera_Pavlovna [14]
3 years ago
5

Help pls I have more ​

Mathematics
2 answers:
IgorC [24]3 years ago
7 0

Answer:

\frac{5}{10}  \times  \frac{2}{1}  =  \frac{10}{10}  = 1

\frac{1}{10}  \times  \frac{8}{3}  =  \frac{8}{30}  =  \frac{4}{15}

\frac{2}{6}  \times  \frac{12}{6}  =  \frac{24}{36}  =  \frac{2}{3}

\frac{1}{4}  \times  \frac{1}{3}  =  \frac{1}{12}

\frac{1}{5}  \times  \frac{1}{1}  =  \frac{1}{5}

earnstyle [38]3 years ago
3 0

Answer:

Step-by-step explanation:

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Use the figure below to find the value of y and each angle shown.
igomit [66]

5y - 16 + 3y + 20 = 180 degrees

Combine like terms on the left side

8y + 4 = 180

Subtract 4 from both sides.

8y = 176

Divide both sides by 8

y = 22

Plug 22 into y for each angle.

3y + 20 = 3(22) + 20 = 66 + 20 = 86 degrees

5y - 16 = 5(22) - 16 = 110 - 16 = 94

The angle opposite 5y - 16 also equals 94 because they are vertical angles.

The angle opposite of 3y + 20 also equals 86 because they are vertical angles

6 0
3 years ago
Does a=2.1 b=7.2 c=7.5 form a right triangle
Anna007 [38]

Answer:

Yes

Step-by-step explanation:

If the longest side squared is equal to the sum of the squares on the other 2 sides then they form a right triangle

longest side = 7.5

7.5² = 56.25

2.1² + 7.2² = 4.41 + 51.84 = 56.25

Thus the 3 values form a right triangle.

6 0
3 years ago
Read 2 more answers
X+2y=10 6y=--3x+30 Use algebraic rules of equations to predict the solution to the system of equations.
MaRussiya [10]
X + 2y = 10 . . . (1)
6y = -3x + 30 . . . (2)

From (2), 3x + 6y = 30
3(x + 2y = 10)
3 x (1)

Since, the second equation is a multiple of the first equation, the system will have an infinitely number of solutions.
3 0
3 years ago
In the past ten years, the population of a city decreased from 90,000 to 75,000 Find the percent decrease.
vfiekz [6]
The answer is 31.5%.
8 0
3 years ago
Country days scholarship rounds receive a gift of $135000. The money is invested in stock, bonds, and CDs. CDs pay 2.75% interes
Vsevolod [243]

Answer:

  • CDs — $10,000
  • bonds — $80,000
  • stocks — $45,000

Step-by-step explanation:

Let the variables c, b, s represent the dollar amounts invested in CDs, stocks, and bonds, respectively. Then the problem statement gives us 3 relations between these 3 variables:

  c + b + s = 135000 . . . . . . . . . . . . . . . . . total invested

  0.0275c +.045b +0.104s = 8555 . . . . . total income earned

  -c + b = 70000 . . . . . . . . . . . . . . . . . . . . . 70,000 more was in bonds than CDs

Using the third equation to write an expression for b, we can substitute into the other two equations.

  b = 70000 +c . . . . . . . . . . . . . . . . expression we can substitute for b

  c + (70000 +c) +s = 135000 . . . . substitute for b in the first equation

  2c +s = 65000 . . . . . . . . . . . . . . . . [eq4] simplify

  .0275c +.045(70000 +c) +.104s = 8555 . . . . . substitute for b in 2nd eqn

  .0725c +.104s = 5405 . . . . . . . . . . [eq5] simplify

Using [eq4], we can write an expression for s that can be substituted into [eq5].

  s = 65000 -2c . . . . . . . expression we can substitute for s

  0.0725c +0.104(65000 -2c) = 5405

  -0.1355c = -1355 . . . . . . . . . . . . . . . . . . . . subtract 6760, simplify

  c = 1355/.1355 = 10,000

  s = 65000 -2×10000 = 45,000

  b = 70000 +10000 = 80,000

The amounts invested in stocks, bonds, and CDs were $45,000, $80,000, and $10,000, respectively.

_____

Alternatively, you can reduce the augmented matrix for this problem to row-echelon form using any of several calculators or on-line sites. That matrix is ...

\left[\begin{array}{ccc|c}1&1&1&135000\\0.0275&0.045&0.104&8555\\-1&1&0&70000\end{array}\right]

6 0
3 years ago
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