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Elden [556K]
3 years ago
14

) What is the regression equation? Remember, use 3 decimal places for ALL answers. mu^^\^y|x = + x (b) What is the estimated mea

n velocity of objects that are 1.9 megaparsecs from Earth? (c) Can we use the regression equation to estimate the mean velocity of objects that are 2.6 megaparsecs from earth? Yes, we can estimate the mean velocity of objects that are any distance from earth. No, because 2.6 is outside the range of the data values for the explanatory variable. (d) If you were to test the claim that there is a positive linear relationship between the explanatory and response variable, what would your null and alternative hypotheses be? H0: b1 =0 and Ha: b1 < 0 H0: b1 = 0 and Ha: b1 ≠ 0 H0: b1 =0 and Ha: b1 > 0 H0: β1 =0 and Ha: β1 < 0 H0: β1 = 0 and Ha: β1 ≠ 0 H0: β1 =0 and Ha: β1 > 0

Physics
1 answer:
Molodets [167]3 years ago
8 0

Answer:

Explanation:

Attach is A and B

c)  No, because 2.6 is outside the range of the data values for the explanatory variable.

d) H0: β1 =0 and Ha: β1 > 0

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A glass rod is charged by the process of ________. *
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Magnetism.

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3 years ago
An unstoppable object is heading right toward an unmovable object. What's going to happen?
marshall27 [118]

Answer:

In my opinion the unstoppable object will hit the unmovable object and stop but the wheels will still be rolling and trying to move but can't.

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8 0
1 year ago
Utility poles are to be set every 30 meters. How many poles will be set in one mile if one was set at the beginning of the mile)
Zepler [3.9K]

Answer:

53

Explanation:

Because there are 1609.34 meters in a mile. 1609.34÷30=53.64 but because you put one at the beginning of the mile it will stay 53 and not round up to 54

4 0
3 years ago
Read 2 more answers
A projectile is fired with an initial velocity of 450 feet per second at an angle of 70° with the horizontal.
pav-90 [236]
<h2>After 26.28 seconds projectile returns 26.28 seconds.</h2>

Explanation:

Initial velocity = 450 ft/s = 137.16 m/s

Angle, θ = 70°

Consider the vertical motion of projectile,

When the projectile return to the ground we have

           Displacement, s = 0 m

           Acceleration, a = -9.81 m/s²

            Initial velocity, u = 137.16 x sin70 = 128.89 m/s

Substituting in s = ut + 0.5 at²

                s = ut + 0.5 at²

                0 = 128.89 x t + 0.5 x (-9.81) x t²

                t² - 26.28 t = 0

                t ( t- 26.28) = 0

               t = 0 s or t = 26.28 s

After 26.28 seconds projectile returns 26.28 seconds.

5 0
3 years ago
Giving brainliest!! if you answer correctly :) (30pts)
myrzilka [38]

Answer:

mass = 4kg

Explanation:

Kinetic Energy = 1/2 x m x v²

where m = mass and v = velocity

So,

KE = 50

1/2 × m × 5² = 50

1/2 × m × 25 = 50

m = (50 x 2)/25

m = 100/25

m = 4 kg

8 0
2 years ago
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