) What is the regression equation? Remember, use 3 decimal places for ALL answers. mu^^\^y|x = + x (b) What is the estimated mea
n velocity of objects that are 1.9 megaparsecs from Earth? (c) Can we use the regression equation to estimate the mean velocity of objects that are 2.6 megaparsecs from earth? Yes, we can estimate the mean velocity of objects that are any distance from earth. No, because 2.6 is outside the range of the data values for the explanatory variable. (d) If you were to test the claim that there is a positive linear relationship between the explanatory and response variable, what would your null and alternative hypotheses be? H0: b1 =0 and Ha: b1 < 0 H0: b1 = 0 and Ha: b1 ≠ 0 H0: b1 =0 and Ha: b1 > 0 H0: β1 =0 and Ha: β1 < 0 H0: β1 = 0 and Ha: β1 ≠ 0 H0: β1 =0 and Ha: β1 > 0
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To develop this problem it is necessary to apply the concepts related to Wavelength, The relationship between speed, voltage and linear density as well as frequency. By definition the speed as a function of the tension and the linear density is given by
Where,
T = Tension
Linear density
Our data are given by
Tension , T = 70 N
Linear density ,
Amplitude , A = 7 cm = 0.07 m
Period , t = 0.35 s
Replacing our values,
Speed can also be expressed as
Re-arrange to find \lambda
Where,
f = Frequency,
Which is also described in function of the Period as,
Therefore replacing to find
Therefore the wavelength of the waves created in the string is 3.49m
This question involves the concepts of Newton's Second Law of Motion.
The acceleration of the bowling ball will be "0.67 m/s²".
<h3>Newton's Second Law of Motion</h3>According to Newton's Second Law of Motion, when an unbalanced force is applied on an object, it produces an acceleration in it, in the direction of the applied force. This acceleration is directly proportional to the force applied and inversely proportional to the mass of the object. Mathematically,
where,
- a = acceleration = ?
- F = Magnitude of the applied force = 6 N
- m = Mass of the ball = 9 kg
Therefore,
a = 0.67 m/s²
Learn more about Newton's Second Law of Motion here:
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