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bogdanovich [222]
3 years ago
6

if the distance between two objects is doubled, the force of gravitation between them becomes __________ of initial value.

Physics
1 answer:
dexar [7]3 years ago
8 0
1/4 of initial time :)
You might be interested in
Why do noble gasses rarely react with other elements?
ollegr [7]
Noble gasses have an outer shell full of electrons. A full outer energy level is the most stable arrangement of electrons. As a result, noble gases cannot become more stable by reacting with other elements and gaining or losing valence electrons. Therefore, noble gases are rarely involved in chemical reactions and almost never form compounds with other elements.
3 0
2 years ago
PLEASE HELP!!!
lilavasa [31]

Answer:

ω = 3.1 rad/s

θ = 36° from vertical

Explanation:

I will ASSUME that the bob and string is acting as a pendulum.

Please understand that the string will break when the bob is at the lowest point of the swing where the vectors of gravity and centripetal acceleration align. It will NOT break at the angle of maximum inclination measured from vertical. This angle is only a component of the maximum potential energy that gets converted to maximum kinetic energy at the lowest point of the swing.

At the bottom of the swing, the string must support the weight of the bob plus supply the required centripetal acceleration.

F = mg + mω²R

F/m = g + ω²R

F/m - g = ω²R

ω = √((F/m - g)/R)

ω = √((3/0.220 - 9.8)/0.40)

ω = 3.09691...

ω = 3.1 rad/s

Potential energy will convert to kinetic energy

       mgh = ½mv²

             h = v²/2g

R - Rcosθ = v²/2g

R(1 - cosθ) = v²/2g

   1 - cosθ = v²/2gR

        cosθ = 1 - v²/2gR

        cosθ = 1 - (Rω)²/2gR

        cosθ = 1 - Rω²/2g

        cosθ = 1 - 0.40(3.1²)/(2(9.8))

        cosθ = 0.804267

              θ = 36.46045...

              θ = 36°

7 0
2 years ago
A girl rode a scooter 43 m north, then 38 m south, and then 16 m north. The girl then rode south again before stopping. Her tota
Vlada [557]

Answer:

First, let's write some definitions.

Displacement is the distance between the final position and the initial position.

Here we can define north as the positive direction and south as the negative one.

First, we assume that the initial position is 0m

We know that she first goes 43m north

Then she goes 38m south

Then she goes 16m north

And then she goes south again for X meters, such that the total distance traveled is 122m

The total distance traveled is the sum of all distances traveled, regardless of the direction

then we have:

43m + 38m + 16m + X = 122m

Solving this for X we get:

97m + X = 122m

X = 122m - 97m = 25m

So she finally goes 25m south.

Now let's analyze how her position changes:

First, she starts at 0m

Then she goes north for 43m, then her new position is:

0m + 43m = 43m

Now she goes 38m south, then her new position is:

43m - 38m = 5m

Then she goes north again, for 16m

Then the new position is:

5m + 16m = 21m

Now she goes south for 25m, then the final position is:

21m - 25m = -4m

The displacement is equal to the difference between the final position and the initial one, so the displacement is:

-4m - 0m = -4m

The displacement is -4m.

8 0
3 years ago
I need help with :
STatiana [176]
I think one popular definition of acceleration might help you here:

Acceleration = (change in speed) / (time for the change)

Multiply each side of this equation by (time for the change) :

Change in speed = (acceleration) x (time for the change)

The problem gives you the acceleration and the time, so

Change in speed = (0.73 m/s²) x (7.1 s)  =  5.183 m/s

Before the acceleration, the car's speed was 7.6 m/s . 
Then the car accelerated for a while. 
During the acceleration, its speed grew by 5.183 m/s.
The final speed is  (7.6 + 5.183) =  <u>12.783 m/s</u>  .


8 0
3 years ago
A cylindrical rod with length (1.7 m) and radius (2 cm) is fixed from one end and a mass of (20 kg) is attached to the other fre
belka [17]

Answer:

0.44

Explanation:

Poisson's ratio is:

ν = (3K − E) / 6K

where K is the bulk modulus and E is Young's modulus.

Young's modulus is:

E = FL / (AΔL)

where F is the force, L is the initial length, A is the cross sectional area, and ΔL is the change in length.

E = (20 kg × 9.8 m/s²) (1.7 m) / (π (0.02 m)² × 0.0005 m)

E = 0.530×10⁹ Pa

Bulk modulus is:

K = -ΔP / (ΔV/V)

where ΔP is the change in pressure, ΔV is the change in volume, and V is the initial volume.

K = -(180 atm × 101325 Pa/atm) / (-0.012)

K = 1.52×10⁹ Pa

Therefore, the Poisson's ratio is:

ν = (3(1.52×10⁹ Pa) − 0.530×10⁹ Pa) / 6(1.52×10⁹ Pa)

ν = (3(1.52) − 0.530) / 6(1.52)

ν = 0.442

Rounded to 2 significant figures, the Poisson's ratio is 0.44.

3 0
3 years ago
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