The time of motion of the ball from the vertical height is independent of the horizontal velocity.
Horizontal moving projectiles is not affected by gravity and the initial velocity is equal to the final velocity.
The time of motion of ball dropped from a vertical height is calculated as follows;
where;
- <em>h </em><em>is the vertical height</em>
- <em>t </em><em>is the </em><em>time </em><em>of motion</em>
- <em>g </em><em>is acceleration due to gravity</em>
- <em />
<em> is the initial </em><em>vertical velocity</em>
From the equation above, we can conclude that time of motion of the ball from the vertical height is independent of the horizontal velocity.
If there is variation in drop time, it could be as a result of applied force when the ball is dropped. This applied force influences the initial velocity which in turn alters the drop time.
Generally, horizontal moving projectiles is not affected by gravity and the initial velocity is equal to the final velocity.
Learn more about horizontal and vertical velocity here: brainly.com/question/14354319
C. plastic. plastic is an insulator!
The refractive index of a material is a dimensionless number that describes how fast light travels through the material. It is defined as n={\frac {c}{v}}, where c is the speed of light in vacuum and v is the phase velocity of light in the medium.
the ratio of the velocity of light in a vacuum to its velocity in a specified medium.
Answer:
a) the magnitude of r is 184.62
b) the direction is 37.74° south of the negative x-axis
Explanation:
Given the data in the question;
as illustrated in the image blow;
To find the the magnitude of r, we will use the Pythagoras theorem
r² = y² + x²
r = √( y² + x²)
we substitute
r = √((-113)² + (-146)²)
r = √(12769 + 21316 )
r = √(34085 )
r = 184.62
Therefore, the magnitude of r is 184.62
To find its direction, we need to find ∅
from SOH CAH TOA
tan = opposite / adjacent
tan∅ = -113 / -146
tan∅ = 0.77397
∅ = tan⁻¹( 0.77397 )
∅ = 37.74°
Therefore, the direction is 37.74° south of the negative x-axis
Buhrs atomic model differed from ruthofords because it explained that electrons exist in specified energy levels surrounding the nucleus. This means that, Ruthoford believed that electrons can't do very much. However, Buhrs' model showed that electrons are much more powerful than anyone else believes they can be.
