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3 years ago

What determines the properties of elements?

Physics

2 answers:

ch4aika [34]3 years ago

7 0

Answer : The correct option is, the number of electrons that fill the outer shell.

Explanation :

Element : It is a pure substance which is composed of atoms of similar elements.

The elements of similar characteristics have same number of valence electrons.

As we know that in the formation of compound the number of valence electrons participate in the bonding. So, the number of electrons that fill the outer shell determines the properties of elements.

Hence, the correct option is, the number of electrons that fill the outer shell.

olasank [31]3 years ago

6 0

the number of electrons that fill the outer shell determines the properties of elements

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A wad of clay of mass m1 = 0.49 kg with an initial horizontal velocity v1 = 1.89 m/s hits and adheres to the massless rigid bar

notka56 [123]

Answer:

<h2>The angular velocity just after collision is given as</h2><h2> $\omega = 0.23 rad/s$ </h2><h2>At the time of collision the hinge point will exert net external force on it so linear momentum is not conserved</h2>

Explanation:

As per given figure we know that there is no external torque about hinge point on the system of given mass

So here we will have

$L_i = L_f$

now we can say

$m_1v_1\frac{L}{2} = (m_2L^2 + m_1(\frac{L}{2})^2)\omega$

so we will have

$0.49(1.89)(0.45) = (2.13(0.90)^2 + 0.49(0.45)^2)\omega$

$\omega = 0.23 rad/s$

Linear momentum of the system is not conserved because at the time of collision the hinge point will exert net external force on the system of mass

So we can use angular momentum conservation about the hinge point

6 0

3 years ago

A fire hose sends 2429 gallons of water per minute against a burning building. The water strikes the building at 66 m/s and does

Anastasy [175]

Answer:

a) Δp = - 10113.2 Kg m / s, b) he rate of change is negative, c) F = 140.46N

Explanation:

a) For this part let's analyze a water particle, it has a velocity of 66 m / s and when it collides with the building its velocity changes to zero, so the change in moment is

Δp = mv_f - m v₀

Δp = -m v₀ (1)

the change of the moment in a second is

if 2429 gallons arrive in in minute (60s) in a second how many gallons arrive

c_agua = 2429/60

c_water = 40,483 gallon/ s

let's use the concept of density to find the mass

ρ = m / V

m = ρ V

let's reduce gallons to liters

c_water = 40,483 gal (3,785 l / 1 gal) = 153.23 l

m = 1 153.23

m 153.23 kg

we substitute in 1

Δp = - 153.23 66

Δp = - 10113.2 Kg m / s

b) From the previous result the rate of change is negative

c) Let's use the impulse ratio

I = f t = Δp

F t = Δp

F = Δp / t

F = $\frac{10113.2}{1.2 \ 60}$

F = 140.46 N

5 0

3 years ago

An electric field of 1139 V/m is applied to a section of silver of uniform cross section. Find the resulting current density if

N76 [4]

Answer:

So, you're going to need the equation ρ = ρo [1 + α(T-To)]

1.59x10^-8 ohms*m is your ρo because that is measured at your reference temperature (To), 20◦C. T is your 6◦C and α is 0.0038(◦C)−1. So, using that you solve for ρ. If you keep up with the units though, you notice it comes out to be ohms*m and that isn't what you want.

So, the next equation you need is J=σE where E is your electric field (3026 V/m) and σ is the electrical conductivity which is the inverse of your answer you got in the previous equation. So find the inverse of that answer and multiply it by your electric field and that will give you the current density.

I hope this helps!

Explanation:

8 0

3 years ago

shows an Atwood machine that consists of two blocks (of masses m1 and m2) tied together with a massless rope that passes over a

taurus [48]

Answer:

Shows an atwood machine that consists of two blocks (of masses m1 and m2) tied together with a massless rope that passes over a fixed, perfect (massless and frictionless) pulley. in this problem you'll investigate some special cases where physical variables describing the atwood machine take on limiting values. often, examining special cases will simplify a problem, so that the solution may be found from inspection or from the results of a problem you've already seen. for all parts of this problem, take upward to be the positive direction and take the gravitational constant, g, to be positive.

part a consider the case where m1 and m2 are both nonzero, and m2> m1. let t1 be the magnitude of the tension in the rope connected to the block of mass m1, and let t2 be the magnitude of the tension in the rope connected to the block of mass m2. which of the following statements is true?

consider the case where and are both nonzero, and . let be the magnitude of the tension in the rope connected to the block of mass , and let be the magnitude of the tension in the rope connected to the block of mass . which of the following statements is true?

a) t1 is always equal to t2.

b) t2 is greater than t1 by an amount independent of velocity.

c) t2 is greater than t1 but the difference decreases as the blocks increase in velocity.

d) there is not enough information to determine the relationship between t1 and t2.

The correct answer to the question is

At equilibrium a) t1 is always equal to t2.

Explanation:

For a Atwood machine we have the masses m₁ and m₂ tied together by a string

Where m₂ > m₁ we take upward to be the positive direction and gravitational constant g = + ve

When in equilibrium, by analyzing the tension in the string, we have

T₁, tension is due to the weight of m₁ and the reaction of m₂

similarly for T₂ tension is due to the weight of m₂ and the reaction of m₁

Since the string is assumed to be weightless and continuous, and the pulley is friction-less, the two weights is therefore supported only by the string hence the tension T₁ and T₂ are equal

5 0

3 years ago

One man pushes on the front of a cart while

geniusboy [140]

Answer:

pushes it forward, pushes it backwards and then it moves

7 0

2 years ago