Answer:
the package has probably not arrived due to mail overloads and packing shortage . mail may be delayed because of external circumstances that change transit times. You can call your local post office to see if your package is there, or wait for your tracking to update to delivered. It will not update to delivered until your mailman actually scans it at your mailbox or door.
Explanation:
Answer:
The distance travel before stopping is 1.84 m
Explanation:
Given :
coefficient of kinetic friction ![\mu_{k} = 0.250](https://tex.z-dn.net/?f=%5Cmu_%7Bk%7D%20%3D%200.250)
Zak's speed ![v = 3 \frac{m}{s}](https://tex.z-dn.net/?f=v%20%3D%203%20%5Cfrac%7Bm%7D%7Bs%7D)
Gravitational acceleration
![\frac{m}{s^{2} }](https://tex.z-dn.net/?f=%5Cfrac%7Bm%7D%7Bs%5E%7B2%7D%20%7D)
Work done by frictional force is given by,
![W = \Delta K](https://tex.z-dn.net/?f=W%20%3D%20%5CDelta%20K)
![\mu _{k} mg d = \frac{1}{2} m v^{2}](https://tex.z-dn.net/?f=%5Cmu%20_%7Bk%7D%20mg%20d%20%3D%20%5Cfrac%7B1%7D%7B2%7D%20m%20v%5E%7B2%7D)
![d = \frac{v^{2} }{2 g \mu _{k} }](https://tex.z-dn.net/?f=d%20%3D%20%5Cfrac%7Bv%5E%7B2%7D%20%20%7D%7B2%20g%20%5Cmu%20_%7Bk%7D%20%7D)
![d = \frac{9}{2 \times 9.8 \times 0.250}](https://tex.z-dn.net/?f=d%20%3D%20%5Cfrac%7B9%7D%7B2%20%5Ctimes%209.8%20%5Ctimes%200.250%7D)
m
Therefore, the distance travel before stopping is 1.84 m
Answer:
+9.8m/s^2
Explanation:
The rate of gravity of the object is constant thriughout the surface of the earth.
For falling object, the rate of gravity is positive since the body is coming down (falling)
The rate of gravity is negative if the body is going up
The constant value for acceleration due to gravity is 9.8m.s^2
Since the object is falling, hence the acceleration due to gravity is positive.
Rate of gravity working on the object will be +9.8m/s^2
Answer:
what's your problem. How may I help you Buddy
Answer:
To find the circumference (orbit) of an object, you use Pi x Diameter.
As you have the circumference of B, you divide it by Pi to get the Diameter.
So 120 divided by 3.141592654 = 38.2 minutes for the Diameter.
As' radius and Diameter will be 3x greater than B.
38.2 x 3 = 114.6
To get back to the orbital period, times 114.6 by Pi, and you will get 360 minutes
HOPE THIS HELPS AND PLS MARK AS BRAINLIEST
THNXX :)