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erik [133]
3 years ago
15

If you walk 8km at an average speed of 4km/h, how much time does it take

Physics
2 answers:
PilotLPTM [1.2K]3 years ago
7 0
Distance = rate x time
8km = 4km/h x time
Time = 2 hours
Galina-37 [17]3 years ago
5 0

Answer:

2 hours

Explanation:

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Which of the following can be used to measure wavelength on a transverse wave
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c. A car was running with a velocity of 20m/s. what will be its velocity after 30s if it's acceleration is 5m/s2​
weqwewe [10]

\large \mathfrak{Solution : }

let's use first equation of motion to solve this ;

  • \boxed{ \boxed{ v = u + at}}

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Velocity after 30 seconds = 170 m/s

4 0
3 years ago
A pupil adds 37g of ice at 0°C to 100g of water at 30°C. The final temperature of the water and melted ice is 0°C. no heat is lo
mojhsa [17]

Answer:

The specific latent heat of ice is approximately 341 J/g

The correct option is;

b) 341 J/g

Explanation:

The given parameters are;

The mass of ice the pupil adds to the water, m₁ = 37 g

The initial temperature of the ice, T₁ = 0°C

The mass of the water to which the ice is added, m₂ = 100 g

The initial temperature of the water, T₂₁ = 30°C

The final temperature of the water and the melted ice, T₂₂ = 0°C

The specific heat capacity of the water, c₂ = 4.2 J/(g·°C)

By the principle of conservation of energy, we have;

The heat gained by the ice = The heat lost by the water = ΔQ₂

Given that the ice is only melted with no change in temperature, we have;

The heat gained by the ice = The latent heat needed for melting the ice

ΔQ₂ = m₂ × c₂ × (T₂₂ - T₂₁) = 100 × 4.2 × (0 - 30) = -12,600 J

The heat gained by the ice = m₁ × L_f

Where;

L_f represents the specific latent heat of fusion of ice;

We have;

12,600 = 37 × L_f

L_f = 12,600/37 = 340.54 J/g ≈ 341 J/g

The specific latent heat of fusion of ice = L_f ≈ 341 J/g.

5 0
3 years ago
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