Ask question

Ask question

All categories

3 years ago

15

If you walk 8km at an average speed of 4km/h, how much time does it take

2 answers:

PilotLPTM [1.2K]3 years ago

7 0

Distance = rate x time
8km = 4km/h x time
Time = 2 hours

Galina-37 [17]3 years ago

5 0

Answer:

2 hours

Explanation:

You might be interested in

What is the definition of displacement

Savatey [412]

<span>the action of moving something from its place or position.</span>

6 0

3 years ago

Read 2 more answers

Light bending at a boundary is caused by differences in the speed of light in different materials. The greater the difference in

olasank [31]

Answer:

How much does light bend? When light travels from air into water, it slows down, causing it to change direction slightly. This change of direction is called refraction. When light enters a more dense substance (higher refractive index), it 'bends' more towards the normal line.

7 0

2 years ago

Did you know that your answer automatically gets reported if you have "idk" anywhere in the answer?

Maurinko [17]

Answer:

rlly??

Explanation:

4 0

3 years ago

Read 2 more answers

In the parallelogram shown, AE = t + 2, CE = 3t − 14, and DE = 2t + 8.

solniwko [45]

The answer would be 48

7 0

4 years ago

Read 2 more answers

A car travels at a steady 40.0 m/s around a horizontal curve of radius 200 m. What is the minimumcoefficient of static friction

zhenek [66]

Answer:

c. 0.816

Explanation:

Let the mass of car be 'm' and coefficient of static friction be 'μ'.

Given:

Speed of the car (v) = 40.0 m/s

Radius of the curve (R) = 200 m

As the car is making a circular turn, the force acting on it is centripetal force which is given as:

Centripetal force is, $F_c=\frac{mv^2}{R}$

The frictional force is given as:

Friction = Normal force × Coefficient of static friction

$f=\mu N$

As there is no vertical motion, therefore, $N=mg$ . So,

$f=\mu mg$

Now, the centripetal force is provided by the frictional force. Therefore,

Frictional force = Centripetal force

$f=F_c\\\\\mu mg=\frac{mv^2}{R}\\\\\mu=\frac{v^2}{Rg}$

Plug in the given values and solve for 'μ'. This gives,

$\mu = \frac{(40\ m/s)^2}{200\ m\times 9.8\ m/s^2}\\\\\mu=\frac{1600\ m^2/s^2}{1960\ m^2/s^2}\\\\\mu=0.816$

Therefore, option (c) is correct.

7 0

4 years ago