Answer:
The water is 1310.75 meters deep.
Explanation:
The question gives us the speed of sound and the time the sonar signal takes to travel to the bottom of the water and back.
To find out the distance, we should first divide the time in half, so we only consider the time taken for the sound to reach the bottom of the water body.
This means:
Time = 1.75 / 2 = 0.875 seconds
The distance traveled in this time is:
Distance = Speed * Time
Distance = 1498 * 0.875
Distance = 1310.75 meters
Thus, the water is 1310.75 meters deep.
Here's one easy way:
-- Hang an object from a scale. Write down its weight in air.
-- Keep the object hanging from the scale, but let it down into water,
or whatever fluid you're interested in.
-- Read the scale again. Write down its weight in the fluid.
-- Dry everything off, clean up the lab, and go to your office with your notebook.
-- In your notebook, turn to the page with that day's observations.
Notice that the object's weight in air was greater than its weight in the fluid.
-- Subtract the weight in fluid from the weight in air.
The difference is the buoyant force on the object when it's in the fluid.
<span>Colloid, in chemistry definition is a heterogenous
mixture, of one substance is different from another, when mixed, either of the
substance (particularly the solid one), is evenly mixed with each other. It
could clearly be seen when one mixes a solution in a suspension state because
it forms a cloudy solution, however, in like suspension, it does not settle at
the bottom of the mixture. Best example of this is milk. When you mix milk
powder to a hot water, the solution is mixed evenly however the color of the
water from transparent changes to milkish white.</span>
Answer:
A) U₀ = ϵ₀AV²/2d
B) U₁ = (ϵ₀AV²)/6d
This means that the new energy of the capacitor is (1/3) of the initial energy before the increased separation.
C) U₂ = (kϵ₀AV²)/2d
Explanation:
A) The energy stored in a capacitor is given by (1/2) (CV²)
Energy in the capacitor initially
U₀ = CV²/2
V = voltage across the plates of the capacitor
C = capacitance of the capacitor
But the capacitance of a capacitor depends on the geometry of the capacitor is given by
C = ϵA/d
ϵ = Absolute permissivity of the dielectric material
ϵ = kϵ₀
where k = dielectric constant
ϵ₀ = permissivity of free space/air/vacuum
A = Cross sectional Area of the capacitor
d = separation between the capacitor
If air/vacuum/free space are the dielectric constants,
So, k = 1 and ϵ = ϵ₀
U₀ = CV²/2
Substituting for C
U₀ = ϵ₀AV²/2d
B) Now, for U₁, the new distance between plates, d₁ = 3d
U₁ = ϵ₀AV²/2d₁
U₁ = ϵ₀AV²/(2(3d))
U₁ = (ϵ₀AV²)/6d
This means that the new energy of the capacitor is (1/3) of the initial energy before the increased separation.
C) U₂ = CV²/2
Substituting for C
U₂ = ϵAV²/2d
The dielectric material has a dielectric constant of k
ϵ = kϵ₀
U₂ = (kϵ₀AV²)/2d