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Law Incorporation [45]
3 years ago
5

How to solve this problem step by step

Chemistry
1 answer:
shtirl [24]3 years ago
8 0

Answer:

V_2= 736mL

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to solve this problem by using the combined gas law:

\frac{P_2V_2}{T_2}= \frac{P_1V_1}{T_1}

Thus, we solve for the final volume by solving for V2 as follows:

V_2= \frac{P_1V_1T_2}{T_1P_2}

Now, we plug in the variables to obtain the result in milliliters and making sure we have both temperatures in Kelvins:

V_2= \frac{1.20atm*735mL*279K}{(112+273)K*660/760atm}\\\\V_2= \frac{1.20atm*735mL*279K}{(112+273)K*660/760atm}=736mL

Regards!

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SO2 reacts with O2 to produce SO3. If 86.0 g of SO2 is placed in a reaction vessel along with excess oxygen gas, how many moles
Salsk061 [2.6K]

Answer:

0,72 moles of SO₂ remain

Explanation:

The reaction is:

2SO₂ + O₂ → 2SO₃

Where molecular mass of SO₂ is 64,066g/mol and of SO₃ is 80,066g/mol.

86,0g of SO₂ are:

86,0g × (1mol / 64,066g) = <em>1,34 moles of SO₂</em>.

50,0g of SO₃ are:

50,0g × (1mol / 80,066g) = <em>0,62 moles of SO₃</em>.

Now, as 2 moles of SO₂ produce 2 moles of SO₃, the moles of SO₂ that remain after the reaction are the initial moles of SO₂ - moles of SO₃:

1,34 moles - 0,62 moles =

<em>0,72 moles of SO₂ remain</em>

I hope it helps!

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3 years ago
How can plants cause weathering? (1 point)
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Answer:

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Explanation:

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3 years ago
Read 2 more answers
Calculate the standard cell potential (E∘) for the reaction X(s)+Y+(aq)→X+(aq)+Y(s) if K = 8.97×10−3. Express your answer to thr
puteri [66]

Answer: The standard cell potential (E∘) for the reaction X(s)+Y^+(aq)\rightarrow X^+(aq)+Y(s)  is -0.121 V

Explanation:

The reaction is:

X(s)+Y^+(aq)\rightarrow X^+(aq)+Y(s)

Relation between standard Gibbs free energy and equilibrium constant follows:

\Delta G^o=-RT\ln K

where,

\Delta G^o = Standard Gibbs free energy = ?

R = Gas constant = 8.314J/K mol

T = temperature = 298 K

K= equilibrium constant = 8.97\times 10^{-3}

Putting values in above equation, we get:

\Delta G^0=-(8.314J/Kmol\times 298K\times \ln (8.97\times 10^{-3})\\\\\Delta G^0=11678.9J/mol

To calculate standard Gibbs free energy, we use the equation:

\Delta G^o=-nFE^o_{cell}

Where,

n = number of electrons transferred = 1

F = Faradays constant = 96500 C

E^o_{cell} = standard cell potential = ?

Putting values in above equation, we get:

11678.9J/mol=-1\times 96500\times E^0_{cell}

\frac{11678.9J/mol}{-96500}=E^0_{cell}

-0.121V=E^0_{cell}

Thus standard cell potential (E∘) for the reaction X(s)+Y^+(aq)\rightarrow X^+(aq)+Y(s)  is -0.121 V

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What gas on earth acts like a metal in the atmosphere of Jupiter?
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About 97.5% of Earth’s water is
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Answer: Water

Explanation:

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