Answer:
0,72 moles of SO₂ remain
Explanation:
The reaction is:
2SO₂ + O₂ → 2SO₃
Where molecular mass of SO₂ is 64,066g/mol and of SO₃ is 80,066g/mol.
86,0g of SO₂ are:
86,0g × (1mol / 64,066g) = <em>1,34 moles of SO₂</em>.
50,0g of SO₃ are:
50,0g × (1mol / 80,066g) = <em>0,62 moles of SO₃</em>.
Now, as 2 moles of SO₂ produce 2 moles of SO₃, the moles of SO₂ that remain after the reaction are the initial moles of SO₂ - moles of SO₃:
1,34 moles - 0,62 moles =
<em>0,72 moles of SO₂ remain</em>
I hope it helps!
Answer: The standard cell potential (E∘) for the reaction
is -0.121 V
Explanation:
The reaction is:
Relation between standard Gibbs free energy and equilibrium constant follows:

where,
= Standard Gibbs free energy = ?
R = Gas constant = 
T = temperature = 298 K
K= equilibrium constant = 
Putting values in above equation, we get:

To calculate standard Gibbs free energy, we use the equation:

Where,
n = number of electrons transferred = 1
F = Faradays constant = 96500 C
= standard cell potential = ?
Putting values in above equation, we get:



Thus standard cell potential (E∘) for the reaction
is -0.121 V
The answer to your question is liquid hydrogen