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likoan [24]
3 years ago
11

Is the relationship between the side length of a square and the area of a square proportional?

Mathematics
1 answer:
Vsevolod [243]3 years ago
3 0

Answer:

Students make in-out tables to assist them in noticing patterns and generalizing the mathematical relationships. Expect students to discover that area increases proportionally to the square of how much the side length increases.)

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A ball thrown in the air has a height of y = - 16x² + 50x + 3 feet after x seconds. a) What are the units of measurement for the
Lubov Fominskaja [6]
<h2>Answer:</h2>

(a) ft/s

(b) 1ft/s

<h2>Step-by-step explanation:</h2>

Given equation;

y = (- 16x² + 50x + 3)ft       -------------(i)

Where;

y is measured in feet(ft)

x is measured in seconds(s).

(a) The rate of change of y with respect to x is found by dividing the total change in y by the total change in x. i.e

Δy / Δx

Where;

Δy = y₂ - y₁  

Δx = x₂ - x₁

∴ Δy / Δx = \frac{y_2 - y_1}{x_2 - x_1}              --------------(ii)

Since y is measured in feet, Δy will also be measured in feet.

Also, since x is measured in seconds, Δx will also be measured in seconds.

Therefore, the rate of change of y with respect to x (Δy / Δx) will be measured in feet per second (ft/s)

(b) The rate of change of y between x  = 0 and x = 2 can be found by using equation (ii)

Where;

y₂ is the value of y at x = 2 found by substituting x = 2 into equation (i)

y₁ is the value of y at x = 0 found by substituting x = 0 into equation (i)

=> y₂ =  - 16(2)² + 50(2) + 3 = 39

=> y₁ =  - 16(1)² + 50(1) + 3 = 37

Now, substitute the values of y₂, y₁, x₂ and x₁  into equation (ii)

Δy / Δx = \frac{39 - 37}{2 - 0}  

Δy / Δx = \frac{2}{2}

Δy / Δx = 1

Therefore, the rate of change of y is 1 ft/s

 

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The cube has side lengths of 1 unit . What is the volume of the cube
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One.

To find the area of a 3D object you multiply length, width, and hight.

So 1 x 1 x 1 = 1

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