The cycle of day and night is a result of Earth’s spinning on its axis, which is Earth’s .

Organism undergo constant chemical changes as they maintain an internal balance known as?

Aleks04 [339]

The answer is homeostasis.

3 0

3 years ago

A pitcher throws a 0.140 kg baseball, and it approaches the bat at a speed of 35.0 m/s. The bat does Wnc = 75.0 J of work on the

Eva8 [605]

Answer:

The speed of the ball is 42.5 m/s

Explanation:

The initial kinetic energy of the ball is:

$K_1=\frac{1}{2} m v_0^2=\frac{1}{2}*0.140 kg*(35.0 m/s)^2$ = 85.75 J

The speed of the ball after leaving the bat is:

$K_2=K_1+W_{nc}\\ \frac{1}{2}mV^2= 85.75 J + 75 J\\ (\frac{1}{2}mV^2)2=( 160.75 J)2\\ mV^2= 321.5 J\\ V^2= \frac{321.5 J}{0.140kg} \\ V=\sqrt{\frac{321.5 J}{0.140kg}}$

V=47.92 m/s

Using kinematic equation we can find the speed of the ball after being 25 m above the point of collision:

$V_f^2-V^2=-2gh$

$V_f^2-(47.92 m/s)^2=-2*9.81m/s^2*25m$

$V_f^2=-2*9.81m/s^2*25m+(47.92 m/s)^2$

$V_f=\sqrt{-2*9.81m/s^2*25m+(47.92 m/s)^2}$

$V_f=42.5m/s$

3 0

3 years ago

The power supply for your answering machine is a small black cube that plugs directly into an electric outlet. The main componen

svet-max [94.6K]

If the transformer’s primary coil has 20 times as many turns of wire in it as the secondary coil has, then the secondary coil provides a small voltage rise for the large amount of current that flows through it.

Answer: Option B

<u>Explanation:</u>

A transformer has a two types of coils, the first one is primary coils and the second one is secondary coil. A secondary coils with hardly any turns in it provides the charges going through it just limited quantities of energy.

Without a long separation over which to do chip away at the charges streaming in the loop, the transformer delivers just a little ascent in the voltage of those charges. Be that as it may, the coil can give this little voltage to ascend to a huge current without requiring an excess of power supply from the input circuit.

4 0

3 years ago

If the ladybug has a mass of 6.0 kg and is at a distance r = 1 m, find her A) velocity, B) centripetal acceleration, and C) cent

Dominik [7]

a) 3.14 m/s

b) $9.9 m/s^2$

c) 59.4 N

Explanation:

a)

The relationship between angular velocity and linear velocity for an object in circular motion is given by:

$v=\omega r$

where

$\omega$ is the angular velocity

v is the linear velocity

r is the distance between the object and the axis of rotation

For the ladybug in this problem, we have:

r = 1 m (distance)

$\omega=3.14 rad/s$ (angular velocity)

So, its linear velocity is

$v=(3.14)(1)=3.14 m/s$

b)

The centripetal acceleration of an object in circular motion is given by the equation

$a=\frac{v^2}{r}$

where

v is the linear velocity

r is the distance between the object and the axis of rotation

The centripetal acceleration represents the radial acceleration of the object.

For the ladybug in this problem, we have:

v = 3.14 m/s (linear velocity)

r = 1 m (distance)

So, the centripetal acceleration is

$a=\frac{3.14^2}{1}=9.9 m/s^2$

c)

The centripetal force for an object in circular motion is given by

$F=ma$

where

m is the mass of the object

a is the centripetal acceleration of the object

The centripetal force is the radial inward force that keeps the object in circular motion.

For the ladybug in this problem we have

m = 6.0 kg (mass)

$a=9.9 m/s^2$ (centripetal acceleration)

So, the centripetal force is

$F=(6.0)(9.9)=59.4 N$

6 0

3 years ago

What is the speed of a 10.0 Hz wave with a wavelength of 2.5 m?

Ilya [14]

Electromagnetic (EM) frequency = f Hz
Wavelength = λ m
f = c / λ, c = f λ:
$hz = {s}^{ - 1} \\ c = 10.0 \: {s}^{ - 1} \times 2.5 \: m = 25 \: \frac{m}{s}$

8 0

3 years ago