In order to increase muscular endurance, it is important to take part in activities that increase the size of muscle cells and the amount of blood that is delivered to the cells<span>. The increased size of the muscle cells reuires them to contract less to accomplish the same task; moreover, the increased blood flow helps deliver oxygen and nutrients to the blood.</span>
Answer:
Power= 6.84×10⁸ W
Explanation:
Given Data
Niagara falls at rate of=1.4×10⁶ kg/s
falls=49.8 m
To find
Power Generated
Solution
Regarding this problem
GPE (gravitational potential energy) declines each second is given from that you will find much the kinetic energy of the falling water is increasing each second.
So power can be found by follow
Power= dE/dt = d/dt (mgh)
Power= gh dm/dt
Power= 1.4×10⁶ kg/s × 9.81 m/s² × 49.8 m
Power= 6.84×10⁸ W
Answer:
D) 720 kmph
Explanation:
First, let's find what distance this aeroplane covered. Distance (d) is the product of speed and time - here, we have a speed of 240 kmph and a time of 5 hours, gives us
km
Using that same fact, we can set up a new equation to solve for speed (s) when we have a distance of 1200 km and a time of 1 2/3 hours. For the sake of cleanliness, I'm gonna rewrite 1 2/3 as the improper fraction 5/3:
Multiplying both sides of the equation by 3/5:
kmph
So our answer is D.
Answer:
1.) Time = 3.5 seconds
2.) Range = 21 m
3.) Velocity = 34.8 m/s
Explanation:
Given that the
Height h = 60 m
Initial velocity U = 6 m/s
1.) The time taken to hit the river for a single droplet of water can be achieved by using second equation of motion
h = Ut + 1/2gt^2
Let assume that the water drops from rest. Therefore, U = 0
60 = 1/2 × 9.8t^2
60 = 4.9t^2
t^2 = 60/4.9
t^2 = 12.24
t = sqrt (12.24)
t = 3.5s
2.) The range of the projectile for a single droplet of water will be calculated by using the formula
R = Ut
Range R = 6 × 3.5 = 20.99
Range = 21 m
3.) The velocity (diagonal) when it hits the water.
Using third equation of motion
V^2 = U^2 + 2gH
Substitute values into the equation
V^2 = 6^2 + 2 × 9.8 × 60
V^2 = 36 + 1176
V^2 = 1212
V = sqrt (1212)
V = 34.8 m/s
