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GalinKa [24]
3 years ago
9

Drag each label to the correct location on the chart. Each label can be used more than once.

Physics
1 answer:
Vadim26 [7]3 years ago
8 0

Answer:

Check Explanation

Explanation:

The waves to be classified are missing from this questions. So, I'll just explain what Transverse and Longitudinal waves are together with examples for each.

A transverse wave is one in which the direction of travel of the wave/disturbance is perpendicular to the direction of the primary cause of the wave/disturbance. The oscillations/vibrations of the wave are perpendicular to the path of propagation or direction of the wave.

Examples include all electromagnetic waves (radio waves, infrared rays, visible light, ultraviolet rays, x-rays, gamma rays), waves in a string of guitar, ripples on the surface of water, seismic S waves etc.

A Longitudinal Wave is one whose direction of travel of the wave/disturbance is parallel to the direction of the primary cause of the wave/disturbance. The oscillations/vibrations of the wave are parallel to the path of propagation or direction of the wave.

Examples include sound waves, seismic P waves, ultrasound waves etc.

Hope this Helps!!!

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The distance between the lenses in a compound microscope is 18 cm. The focal length of the objective is 1.5 cm. If the microscop
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Answer:

The focal length of eye piece is 6.52 cm.

Explanation:

Given that,

Angular Magnification of the microscope M = -46

the distance between the lens in microscope L= 16 cm

The focal length of objective f₀ = 1.5 cm

Normal near point N = 25 cm

Have to find focal length of eye piece f ₙ =?

The angular magnification is given by

M ≈ - (L-fₙ)N/f₀fₙ

Rearranging for fₙ

fₙ =L(1 - Mf₀/N)⁺¹

   =18/2.76

fₙ =  6.52 cm

The focal length of eye piece is 6.52 cm.

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