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2 years ago

Drag each label to the correct location on the chart. Each label can be used more than once.

Physics

1 answer:

Vadim26 [7]2 years ago

8 0

Answer:

Check Explanation

Explanation:

The waves to be classified are missing from this questions. So, I'll just explain what Transverse and Longitudinal waves are together with examples for each.

A transverse wave is one in which the direction of travel of the wave/disturbance is perpendicular to the direction of the primary cause of the wave/disturbance. The oscillations/vibrations of the wave are perpendicular to the path of propagation or direction of the wave.

Examples include all electromagnetic waves (radio waves, infrared rays, visible light, ultraviolet rays, x-rays, gamma rays), waves in a string of guitar, ripples on the surface of water, seismic S waves etc.

A Longitudinal Wave is one whose direction of travel of the wave/disturbance is parallel to the direction of the primary cause of the wave/disturbance. The oscillations/vibrations of the wave are parallel to the path of propagation or direction of the wave.

Examples include sound waves, seismic P waves, ultrasound waves etc.

Hope this Helps!!!

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Which of the following statements is true regarding the constructive interference diagram shown below? Select all that apply.

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Answer:

I believe its B and C

Explanation:

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2 years ago

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A transverse wave on a string is described by the wave functiony(x, t) = 0.350 sin (1.25x + 99.6t)where x and y are in meters an

ella [17]

The time interval that is between the first two instants when the element has a position of 0.175 is 0.0683.

<h3>How to solve for the time interval</h3>

We have y = 0.175

y(x, t) = 0.350 sin (1.25x + 99.6t) = 0.175

sin (1.25x + 99.6t) = 0.175

sin (1.25x + 99.6t) = 0.5

99.62 = pi/6

t1 = 5.257 x 10⁻³

99.6t = pi/6 + 2pi

= 0.0683

The time interval that is between the first two instants when the element has a position of 0.175 is 0.0683.

b. we have k = 1.25, w = 99.6t

v = w/k

99.6/1.25 = 79.68

s = vt

= 79.68 * 0.0683

= 5.02

Read more on waves here

brainly.com/question/25699025

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complete question

A transverse wave on a string is described by the wave function y(x, t) = 0.350 sin (1.25x + 99.6t) where x and y are in meters and t is in seconds. Consider the element of the string at x=0. (a) What is the time interval between the first two instants when this element has a position of y= 0.175 m? (b) What distance does the wave travel during the time interval found in part (a)?

7 0

1 year ago

A baseball player leads off the game and hits a long home run. The ball leaves the bat at an angle of 70.0 from the horizontal w

professor190 [17]

Answer: 211.059 m

Explanation:

We have the following data:

$\theta=70\°$ The angle at which the ball leaves the bat

$V_{o}=55 m/s$ The initial velocity of the ball

$g=-9.8 m/s^{2}$ The acceleration due gravity

We need to find how far (horizontally) the ball travels in the air: $x$

Firstly we need to know this velocity has two components:

Horizontally:

$V_{ox}=V_{o}cos \theta$ (1)

$V_{ox}=55 m/s cos(70\°)=18.811 m/s$ (2)

Vertically:

$V_{oy}=V_{o}sin \theta$ (3)

$V_{oy}=55 m/s sin(70\°)=51.683 m/s$ (4)

On the other hand, when we talk about parabolic movement (as in this situation) the ball reaches its maximum height just in the middle of this parabola, when $V=0$ and the time $t$ is half the time it takes the complete parabolic path.

So, if we use the following equation, we will find $t$ :

$V=V_{o}+gt=0$ (5)

Isolating $t$ :

$t=\frac{-V_{o}}{g}$ (6)

$t=\frac{-55 m/s}{-9.8 m/s^{2}}$ (7)

$t=5.61 s$ (8)

Now that we have the time it takes to the ball to travel half of is path, we can find the total time $T$ it takes the complete parabolic path, which is twice $t$ :

$T=2t=2(5.61 s)=11.22 s$ (9)

With this result in mind, we can finally calculate how far the ball travels in the air:

$x=V_{ox}T$ (10)

Substituting (2) and (9) in (10):

$x=(18.811 m/s)(11.22 s)$ (11)

Finally:

$x=211.059 m$

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2 years ago

What is the name of the force that is a combination of all forces that act on an object?

jarptica [38.1K]

Answer:

If the combination of all the forces acting on an object sums upto be zero, then the net force is known as balanced force.

If the combination of all the forces acting on an object is non-zero, then the net force is said to be unbalanced force. The unbalanced force causes the object change the state of rest or motion.

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3 years ago