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GalinKa [24]
2 years ago
9

Drag each label to the correct location on the chart. Each label can be used more than once.

Physics
1 answer:
Vadim26 [7]2 years ago
8 0

Answer:

Check Explanation

Explanation:

The waves to be classified are missing from this questions. So, I'll just explain what Transverse and Longitudinal waves are together with examples for each.

A transverse wave is one in which the direction of travel of the wave/disturbance is perpendicular to the direction of the primary cause of the wave/disturbance. The oscillations/vibrations of the wave are perpendicular to the path of propagation or direction of the wave.

Examples include all electromagnetic waves (radio waves, infrared rays, visible light, ultraviolet rays, x-rays, gamma rays), waves in a string of guitar, ripples on the surface of water, seismic S waves etc.

A Longitudinal Wave is one whose direction of travel of the wave/disturbance is parallel to the direction of the primary cause of the wave/disturbance. The oscillations/vibrations of the wave are parallel to the path of propagation or direction of the wave.

Examples include sound waves, seismic P waves, ultrasound waves etc.

Hope this Helps!!!

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Which of the following statements is true regarding the constructive interference diagram shown below? Select all that apply.
yulyashka [42]

Answer:

I believe its B and C

Explanation:

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A transverse wave on a string is described by the wave functiony(x, t) = 0.350 sin (1.25x + 99.6t)where x and y are in meters an
ella [17]

The time interval that is between the first two instants when the element has a position of 0.175 is 0.0683.

<h3>How to solve for the time interval</h3>

We have y = 0.175

y(x, t) = 0.350 sin (1.25x + 99.6t) = 0.175

sin (1.25x + 99.6t) = 0.175

sin (1.25x + 99.6t) = 0.5

99.62 = pi/6

t1 = 5.257 x 10⁻³

99.6t = pi/6 + 2pi

= 0.0683

The time interval that is between the first two instants when the element has a position of 0.175 is 0.0683.

b. we have k = 1.25, w = 99.6t

v = w/k

99.6/1.25 = 79.68

s = vt

= 79.68 * 0.0683

= 5.02

Read more on waves here

brainly.com/question/25699025

#SPJ4

complete question

A transverse wave on a string is described by the wave function y(x, t) = 0.350 sin (1.25x + 99.6t) where x and y are in meters and t is in seconds. Consider the element of the string at x=0. (a) What is the time interval between the first two instants when this element has a position of y= 0.175 m? (b) What distance does the wave travel during the time interval found in part (a)?

7 0
1 year ago
A baseball player leads off the game and hits a long home run. The ball leaves the bat at an angle of 70.0 from the horizontal w
professor190 [17]

Answer: 211.059 m

Explanation:

We have the following data:

\theta=70\° The angle at which the ball leaves the bat

V_{o}=55 m/s The initial velocity of the ball

g=-9.8 m/s^{2} The acceleration due gravity

We need to find how far (horizontally) the ball travels in the air: x

Firstly we need to know this velocity has two components:

<u>Horizontally:</u>

V_{ox}=V_{o}cos \theta (1)

V_{ox}=55 m/s cos(70\°)=18.811 m/s (2)

<u>Vertically:</u>

V_{oy}=V_{o}sin \theta (3)

V_{oy}=55 m/s sin(70\°)=51.683 m/s (4)

On the other hand, when we talk about parabolic movement (as in this situation) the ball reaches its maximum height just in the middle of this parabola, when V=0 and the time t is half the time it takes the complete parabolic path.

So, if we use the following equation, we will find t:

V=V_{o}+gt=0 (5)

Isolating t:

t=\frac{-V_{o}}{g} (6)

t=\frac{-55 m/s}{-9.8 m/s^{2}} (7)

t=5.61 s (8)

Now that we have the time it takes to the ball to travel half of is path, we can find the total time T it takes the complete parabolic path, which is twice t:

T=2t=2(5.61 s)=11.22 s (9)

With this result in mind, we can finally calculate how far the ball travels in the air:

x=V_{ox}T (10)

Substituting (2) and (9) in (10):

x=(18.811 m/s)(11.22 s) (11)

Finally:

x=211.059 m

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What is the name of the force that is a combination of all forces that act on an object?
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Answer:

If the combination of all the forces acting on an object sums upto be zero, then the net force is known as <u>balanced force.</u>

If the combination of all the forces acting on an object is non-zero, then the net force is said to be <u>unbalanced force. </u>The unbalanced force causes the object change the state of rest or motion.

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