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3 years ago

Drag each label to the correct location on the chart. Each label can be used more than once.

Physics

1 answer:

Vadim26 [7]3 years ago

8 0

Answer:

Check Explanation

Explanation:

The waves to be classified are missing from this questions. So, I'll just explain what Transverse and Longitudinal waves are together with examples for each.

A transverse wave is one in which the direction of travel of the wave/disturbance is perpendicular to the direction of the primary cause of the wave/disturbance. The oscillations/vibrations of the wave are perpendicular to the path of propagation or direction of the wave.

Examples include all electromagnetic waves (radio waves, infrared rays, visible light, ultraviolet rays, x-rays, gamma rays), waves in a string of guitar, ripples on the surface of water, seismic S waves etc.

A Longitudinal Wave is one whose direction of travel of the wave/disturbance is parallel to the direction of the primary cause of the wave/disturbance. The oscillations/vibrations of the wave are parallel to the path of propagation or direction of the wave.

Examples include sound waves, seismic P waves, ultrasound waves etc.

Hope this Helps!!!

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Give a calculate answer to show that the two values (English system and metric system) for the Planck Constant are equivalent.

Nataly_w [17]

Answer:

Given values of Planck Constant are equivalent in English system and metric system.

Explanation:

Value of Planck's constant is given in English system as 4.14 x 10⁻¹⁵eV s.

Converting this in to metric system .

We have 1 eV = 1.6 x 10⁻¹⁹ J

Converting

4.14 x 10⁻¹⁵eV s = 4.14 x 10⁻¹⁵x 1.6 x 10⁻¹⁹ = 6.63 x 10⁻³⁴ Joule s

So Given values of Planck Constant are equivalent in English system and metric system.

7 0

3 years ago

Does the theory of relativity show that Newtonian mechanics is wrong?

valina [46]

Answer:

Einstein extended the rules of Newton for high speeds. For applications of mechanics at low speeds, Newtonian ideas are almost equal to reality. That is the reason we use Newtonian mechanics in practice at low speeds.

Explanation:

<em>But on a conceptual level, Einstein did prove Newtonian ideas quite wrong in some cases, e.g. the relativity of simultaneity. But again, in calculations, Newtonian ideas give pretty close to correct answer in low-speed regimes. So, the numerical validity of Newtonian laws in those regimes is something that no one can ever prove completely wrong - because they have been proven correct experimentally to a good approximation.</em>

4 0

3 years ago

A commuter backs her car out of her garage with an acceleration of 1.40 m/s2.A) How long does it take her to reach a speed of 2.

AURORKA [14]

Answer:

(A) 1.43secs

(B) -2.50m/s^2

Explanation:

A commuter backs her car out of her garage with an acceleration of 1.40m/s^2

(A) When the speed is 2.00m/s then, the time can be calculated as follows

t= Vf-Vo/a

The values given are a= 1.40m/s^2 , Vf= 2.00m/s, Vo= 0

= 2.00-0/1.40

= 2.00/1.40

= 1.43secs

(B) The deceleration when the time is 0.800secs can be calculated as follows

a= Vf-Vo/t

= 0-2.00/0.800

= -2.00/0.800

= -2.50m/s^2

4 0

3 years ago

A car is traveling at 10 m/s. 10 seconds later the car is traveling 40 m/s. What is the car’s acceleration?

ratelena [41]

Answer:

a = 3 m/s^2

Explanation:

Vi = 10 m/s

Vf = 40 m/s

t = 10 s

Plug those values into the following equation:

Vf = Vi + at

40 = 10 + 10a

---> a = 3 m/s^2

3 0

3 years ago

Momentum is usually not exactly conserved in a real world demonstration of momentum conservation. What is a possible reason for

Maksim231197 [3]

Answer:

For any collision occurring in an isolated system, momentum is conserved. The total amount of momentum of the collection of objects in the system is the same before the collision as after the collision.

Explanation:

Hope this helps

5 0

3 years ago