When a quadrilateral is inscribed in a circle, the opposite angles are supplementary.
x + 2 + 3x + 6 = 180
4x + 8 = 180
4x = 172
x = 43
Now solve for A
3(43) + 6 = A
129 + 6 = A
135 = A
The measure of angle A is 135 degrees.
Hope this helps =)
Answer:
The values from least to greatest would be 202, 245, 245, 254, 276
The mean would be 244.4
The median would be 245
The mode would be 245
Step-by-step explanation:
To find the mean, you add all the numbers together and divide that sum by the number of numbers. In this case, you add all the numbers together and you get 1222. Next, you divide that by 5 because there are 5 numbers. To find the median, you order the numbers from least to greatest and find the middle number. For this question, the answer would be 245. Lastly, to find the mode you look for the number that appears the most. In this case it's 245.
<em>Last year the chess club had 30 members. This year the club has 24 members. </em>
Last year, the chess club had 30 members. This year, the club has 24 members. Since this year had less than last year ( 30 > 24), the percent will be decreasing.
To find the percent decrease, you have to use the following formula.

Difference refers to the difference between the two numbers, 24 and 30. The difference between 24 and 30 is 6. Original refers to the original number, which is last year's amount of members in the chess group. Therefore, original = 30.
Substitute the numbers into the formula.

To convert the decimal to a fraction, multiply the decimal by 100.

The answer is the number of chess members decreased by 20%.
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Since I started off by identifying whether it was decreasing or increasing, I did the work a bit differently. When finding the difference, you would usually subtract 30 from 24, which results in -6. Above I used 6, but if you used -6, you would end up with a result of -20%, which means it decreased by 20%. They bot end up with the same result, but you don't always have to first identify whether it's decreasing or increasing.
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thats cool did you want to ask a question though?
Oh wait this is confusing.. i think somebody asked this question and got it answered
so search it up on here