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Masteriza [31]
4 years ago
7

the lenses in a students eyes have arefractive power of 52. 0 diopters when she is able to focus on the board if the distance be

tween the ey lens and the retina is 2.00 cm find how
Physics
1 answer:
Kruka [31]4 years ago
3 0

Answer:

     p = 49.95 cm

This is the distance from the student to the stepped, in order to be able to reach this distance they must sit in the first row

Explanation:

In medicine it is very common to express the potential visual corrections that is

         P = 1 / f

where P is the power and f the focal length in meters

In this exercises give the power, let's find the focal length

        f = 1 / p

        f = 1/52

        f = 0.01923 m = 1.923 cm

For geometrical optics calculations the most used equation is the constructor equation

        1 / f = 1 / p + 1 / q

Where p and q are the distance to the object and the image, respectively

To be able to see an object clearly, its image must be on the retina,

       q = 2.00 cm

find the distance to the object

        1 / p = 1 / f - 1 / q

        1 / p = 1 / 1,923 - 1/2.00

        1 / p = 0.02002

         p = 49.95 cm

This is the distance from the student to the stepped, in order to be able to reach this distance they must sit in the first row

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Answer:

I = 2172.46 A

Explanation:

Given that,

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B=\mu_o nI\\\\or\\\\B=\mu_o \dfrac{N}{L}I\\\\I=\dfrac{BL}{\mu_o N}

Put all the values,

I=\dfrac{1.3\times 2.1}{4\pi \times 10^{-7}\times 1000}\\\\I=2172.46\ A

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A car slows down uniformly from a speed of 30.0 m/s to rest in 7.20 s
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where v and v_0 are the final and initial velocities, respectively. By definition, we also have that the average velocity is given by

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where x,x_0 are the final/initial displacements, and t,t_0 are the final/initial times, respectively.

Take the car's starting position to be at t_0=0\,\mathrm s. Then

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x=0\,\mathrm m+\dfrac12\left(0\,\dfrac{\mathrm m}{\mathrm s}+30.0\,\dfrac{\mathrm m}{\mathrm s}\right)(7.20\,\mathrm s)=108\,\mathrm m

You also could have first found the acceleration using the equation

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An object that completes 20 vibrations in 10 seconds has a frequency of
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Answer:

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So f = \frac{20}{10} = 2Hz

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<em>Thus the object has frequency of 2 Hz and time period of 0.5 s.</em>

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3 years ago
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