300N/25 kg= divide them for the answer
A decrease in it's operating temperature would make a heat engine less efficient. This is because in order to operate, a heat engine needs to be hot and maintain that temperature.
If you have no idea what the voltage is that you're about to measure,
then you should set the meter to the highest range before you connect
it to the two points in the circuit.
Analog meters indicate the measurement by moving a physical needle
across a physical card with physical numbers printed on it. If the unknown
voltage happens to be 100 times the full range to which the meter is set,
then the needle may find itself trying to move to a position that's 100 times
past the highest number on the meter's face. You'll hear a soft 'twang',
followed by a louder 'CLICK'. Then you'll wonder why the meter has no
needle on it, and then you'll walk over to the other side of the room and
pick up the needle off the floor, and then you'll probably put the needle
in your pocket. That will end your voltage measurements for that day,
and certainly for that meter.
Been there.
Done that.
The answer you are looking for is B, hope this helps.
Answer:
As the wavelength of an electromagnetic wave _decrease__ the frequency of the wave _increase_______.
Explanation:
What is the relationship between frequency and wavelength?
Wavelength and frequency of light are closely related. The higher the frequency, the shorter the wavelength. Because all light waves move through a vacuum at the same speed, the number of wave crests passing by a given point in one second depends on the wavelength.
That number, also known as the frequency, will be larger for a short-wavelength wave than for a long-wavelength wave. The equation that relates wavelength and frequency is:
V= fλ
where v= velocity
f= frequency
λ = wavelength
⇒ f = v/λ
also f ∝ 1/λ
For electromagnetic radiation, the speed is equal to the speed of light, c, and the equation becomes:
C= fλ
where c= Speed of light
f= frequency
λ = wavelength
⇒ f = v/λ
also f ∝ 1/λ
