A force over distance is work the unite is joules
Let's start with the concept of momentum. What is it? Linear momentum in physics is mathematically written as a product of mass and velocity of an object. Now let us suppose a body of mass m is moving in an inertial frame of reference with velocity v. Consider the fact that no external force is acting on the system. The momentum of this body is given by mv, where m is the mass and v is its velocity. In case of simple real world problems not delving into the realms of relativity, mass is a conserved quantity and it cannot be zero. Hence the velocity of the body must be zero and hence the momentum.
However, photons are considered to have a rest mass zero.
However note the point carefully "rest mass". A body in motion cannot have mass to be zero.
<em>-</em><em> </em><em>BRAINLIEST</em><em> answerer</em><em> ❤️</em>
A, electromagnetic radiation
This may helpv^2=u^2+2as. v=0 at top of flight. a=acceleration of gravity(vo^2)/2a=s.
Answer:
a). Maximum Length L=0.929m
b). T=0.83 Hz or 1.2s
c). Longer, the effortless waling T=2.1 Hz or t=0.475s
d). t=1.2s V=0.774 ![\frac{m}{s}](https://tex.z-dn.net/?f=%5Cfrac%7Bm%7D%7Bs%7D)
t=0.475s V=1.95 ![\frac{m}{s}](https://tex.z-dn.net/?f=%5Cfrac%7Bm%7D%7Bs%7D)
Explanation:
Length legs=L=1.1m
angle=50
the step that give the person forms a triangle whose two sides are known and the angle that forms between them, then using trigonometry as the image
Divide the original triangle in two and form a right triangle so the angle is 25 and the L is hypotenuse and the opposite is the step length
a).
![sin(\alpha) =\frac{op}{h}](https://tex.z-dn.net/?f=sin%28%5Calpha%29%20%3D%5Cfrac%7Bop%7D%7Bh%7D)
![op=h*sin(\frac{\alpha }{2})\\ op=1.1m*sin(\frac{50}{2})\\op=0.464m](https://tex.z-dn.net/?f=op%3Dh%2Asin%28%5Cfrac%7B%5Calpha%20%7D%7B2%7D%29%5C%5C%20op%3D1.1m%2Asin%28%5Cfrac%7B50%7D%7B2%7D%29%5C%5Cop%3D0.464m)
Length of the step
L=0.464m*2
L=0.928m
b).
period=T
![T=\frac{1}{time}=\frac{1}{t}\\ T=\frac{1}{1.2s}\\T=0.83 s^{-1}\\ T=0.83Hz](https://tex.z-dn.net/?f=T%3D%5Cfrac%7B1%7D%7Btime%7D%3D%5Cfrac%7B1%7D%7Bt%7D%5C%5C%20T%3D%5Cfrac%7B1%7D%7B1.2s%7D%5C%5CT%3D0.83%20s%5E%7B-1%7D%5C%5C%20T%3D0.83Hz)
c).
![T1=2\pi *\sqrt{\frac{L}{g}} \\T1=2\pi *\sqrt{\frac{1.1m}{9.8\frac{m}{s^{2}}}}\\ T1=2.1 Hz](https://tex.z-dn.net/?f=T1%3D2%5Cpi%20%2A%5Csqrt%7B%5Cfrac%7BL%7D%7Bg%7D%7D%20%5C%5CT1%3D2%5Cpi%20%2A%5Csqrt%7B%5Cfrac%7B1.1m%7D%7B9.8%5Cfrac%7Bm%7D%7Bs%5E%7B2%7D%7D%7D%7D%5C%5C%20T1%3D2.1%20Hz)
The period is the inverse of the time of the motion so, the T1 is faster that the T because
![t=\frac{1}{T1}=t= \frac{1}{2.1}=0.47s](https://tex.z-dn.net/?f=t%3D%5Cfrac%7B1%7D%7BT1%7D%3Dt%3D%20%5Cfrac%7B1%7D%7B2.1%7D%3D0.47s)
d).
The speed is the relation between the distance with time so:
![Vt=\frac{0.928m}{1.2s} \\Vt=0.773 \frac{m}{s} \\Vt=\frac{0.928m}{0.475s} \\Vt=1.953 \frac{m}{s}](https://tex.z-dn.net/?f=Vt%3D%5Cfrac%7B0.928m%7D%7B1.2s%7D%20%5C%5CVt%3D0.773%20%5Cfrac%7Bm%7D%7Bs%7D%20%5C%5CVt%3D%5Cfrac%7B0.928m%7D%7B0.475s%7D%20%5C%5CVt%3D1.953%20%5Cfrac%7Bm%7D%7Bs%7D)