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zubka84 [21]
3 years ago
14

Someone please help!

Mathematics
2 answers:
finlep [7]3 years ago
4 0

Answer:

3.25

Step-by-step explanation:

it is shrinking by a factor of 4 so every number is 4 times smaller and 13 divided by 4 will give you 3.25

erastovalidia [21]3 years ago
3 0

Answer:

3.25

Step-by-step explanation:

As you can see from the one on the left and the other on the right is that the left is larger than the right by the ratio of 4:1

CB = 12, ZY = 3

BA = 5, YX = 1.25

Using this information, to find ZX, we just need to divide CA's  length by 4:

13 / 4 = 3.25

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MArishka [77]
The equation in slope-intercept is   y=0.625x+7.    


y = mx + b

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m is the slope of the line 
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The slope m of the line through any two points (x1, y1) and (x2, y2) is given by:

The y-intercept b of the line is the value of y at the point where the line crosses the y axis. Since for point (x1, y1) we have y1 = mx1 + b, the y-intercept b can be calculated by:

b = y1 - mx<span>1.    hope that helped</span>

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aleksklad [387]

Answer:

It is equal to each other

Step-by-step explanation:

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insens350 [35]

Answer:

Question 4:  y=\displaystyle -\frac{4}{5}x

Question 5: y=-5x-3

Step-by-step explanation:

Hi there!

Linear equations are typically organized in slope-intercept form: y=mx+b where <em>m</em> is the slope of the line and <em>b</em> is the y-intercept (the y-coordinate of the point where the line crosses the y-axis).

<u>Question 4</u>

<u>1) Determine the slope (</u><u><em>m</em></u><u>)</u>

\displaystyle m=\frac{y_2-y_1}{x_2-x_1} where two points that pass through the line are (x_1,y_1) and (x_2,y_2)

In the graph, two easy-to-identify points on the line are (-5,4) and (5,-4). Plug these into the equation:

\displaystyle m=\frac{-4-4}{5-(-5)}\\\\\displaystyle m=\frac{-4-4}{5+5}\\\\\displaystyle m=\frac{-8}{10}\\\\\displaystyle m=-\frac{4}{5}

Therefore, the slope of the line is \displaystyle -\frac{4}{5}. Plug this into y=mx+b as the slope (<em>m</em>):

y=\displaystyle -\frac{4}{5}x+b

<u>2) Determine the y-intercept (</u><u><em>b</em></u><u>)</u>

On the graph, we can see that the line crosses the y-axis when y is 0. Therefore, the y-intercept (<em>b</em>) is 0. Plug this into y=\displaystyle -\frac{4}{5}x+b:

y=\displaystyle -\frac{4}{5}x+0\\\\y=\displaystyle -\frac{4}{5}x

<u>Question 5</u>

<u>1) Determine the slope (</u><u><em>m</em></u><u>)</u>

\displaystyle m=\frac{y_2-y_1}{x_2-x_1}

Two easy-to-identify points are (-1,2) and (0,-3). Plug these into the equation:

\displaystyle m=\frac{-3-2}{0-(-1)}\\\\\displaystyle m=\frac{-3-2}{0+1}\\\\\displaystyle m=\frac{-5}{1}\\\\m=-5

Therefore, the slope is -5. Plug this into y=mx+b:

y=-5x+b

<u>2) Determine the y-intercept (</u><u><em>b</em></u><u>)</u>

On the graph, we can see that the line crosses the y-axis at the point (0,-3). The y-coordinate of this point is -3. Therefore, the y-intercept (<em>b</em>) is -3. Plug this into y=-5x+b:

y=-5x+(-3)\\y=-5x-3

I hope this helps!

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