A coil of wire is connected to a galvanometer. When the coil is rotated in a magnetic field, the galvanometer records a current
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When the mass is 5.0 cm from its equilibrium point, the percentage of its energy that is kinetic is 75%.
<h3>Total energy of the mass</h3>
The total energy possessed by the mass under the simple harmonic motion is calculated as follows;
U = ¹/₂kA²
where;
- k is the spring constant
- A is the amplitude of the oscillation
P.E = ¹/₂k(Δx)²
<h3>Kinetic energy of mass</h3>K.E = U - P.E
K.E = ¹/₂kA² - ¹/₂k(Δx)²
<h3>Percentage of its energy that is kinetic</h3>Thus, when the mass is 5.0 cm from its equilibrium point, the percentage of its energy that is kinetic is 75%.
Learn more about kinetic energy here: brainly.com/question/25959744
Kepler's third law states that, for a planet orbiting around the Sun, the ratio between the cube of the radius of the orbit and the square of the orbital period is a constant:
(1)
where
r is the radius of the orbit
T is the period
G is the gravitational constant
M is the mass of the Sun
Let's convert the radius of the orbit (the distance between the Sun and Neptune) from AU to meters. We know that 1 AU corresponds to 150 million km, so
so the radius of the orbit is
And if we re-arrange the equation (1), we can find the orbital period of Neptune:
We can convert this value into years, to have a more meaningful number. To do that we must divide by 60 (number of seconds in 1 minute) by 60 (number of minutes in 1 hour) by 24 (number of hours in 1 day) by 365 (number of days in 1 year), and we get
where
r is the radius of the orbit
T is the period
G is the gravitational constant
M is the mass of the Sun
Let's convert the radius of the orbit (the distance between the Sun and Neptune) from AU to meters. We know that 1 AU corresponds to 150 million km, so
so the radius of the orbit is
And if we re-arrange the equation (1), we can find the orbital period of Neptune:
We can convert this value into years, to have a more meaningful number. To do that we must divide by 60 (number of seconds in 1 minute) by 60 (number of minutes in 1 hour) by 24 (number of hours in 1 day) by 365 (number of days in 1 year), and we get