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3 years ago

15

What are generated at transform fault plate boundaries?

1 answer:

tankabanditka [31]3 years ago

5 0

Answer: The Earth's layer, which has the covering and layer, is made of a progression of things, or structural plates, that creep after some time. Along these lines, at intersecting limits, mainland outside is made and maritime covering is devastated. 2 plates slippy past each other structures a redesign plate limit.

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A plane whose air speed is 150 mi/h flew from abbot to blair in 2h with a tail wind. on teh return trip against the same wind, t

dsp73

When plane is flying in tail wind condition we will have

$V_{plane} + v_{wind} = \frac{distance}{time}$

$150 mph + v_{wind} = \frac{distance}{2}$

Now during return journey we can say its would be head wind now

$V_{plane} - v_{wind} = \frac{distance}{time}$

time = 2 + 1 = 2 hours

$150 - v_{wind} = \frac{distance}{3}$

now add two equations

$300 = \frac{5*distance}{6}$

distance = 360 miles

now from above equation again

$v_{wind} = 30 mph$

8 0

3 years ago

What kind of mirror do u think s used in the side-view mirror of cars?

Aloiza [94]

Answer:

The Convex Mirror is used.

Explanation:

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3 years ago

Calculate the momentum for each ocean creature and then answer the question. A 500 kg dolphin swims at 4 m/s. A 700 kg sea turtl

nasty-shy [4]

Sea turtle has the most momentum. I took the quiz and got that one right .

6 0

3 years ago

Read 2 more answers

In Figure 13-2, is the pressure greater in the area of the bottle outside of the tube (D) or inside of the tube (B)?

Alinara [238K]

I could only tell you if i knew what the figure looked like

3 0

4 years ago

Read 2 more answers

The electric field 14.0 cm from the surface of a copper ball of radius 2.0 cm is directed toward the ball's center and has magni

Marina CMI [18]

Answer:

Q = - 256 X 10⁻⁷ C .

Explanation:

Electric field due to a charge Q at a distance d from the center is given by the expression

E = k Q /d² Where k is a constant and it is equal to 9 x 10⁹

Put the given value in the equation

9 x 10² = $\frac{9\times10^9\times Q}{(14+2)^2\times10^{-4}}$

Q = $\frac{9\times16^2\times10^{-2}}{9\times10^9}$

Q = - 256 X 10⁻⁷ C .

It will be negative in nature as the field is directed towards the center.

5 0

3 years ago