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RSB [31]
3 years ago
15

What are generated at transform fault plate boundaries?

Physics
1 answer:
tankabanditka [31]3 years ago
5 0

Answer: The Earth's layer, which has the covering and layer, is made of a progression of things, or structural plates, that creep after some time. Along these lines, at intersecting limits, mainland outside is made and maritime covering is devastated. 2 plates slippy past each other structures a redesign plate limit.

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PLEASE HELP FAST WILL GIVE BRAINLIEST The sentence, "The popcorn kernels popped twice as fast as the last batch," is a(n) _____.
beks73 [17]

The answer is 3. Observation

Explanation:

The sentence "The popcorn kernels popped twice as fast as the last batch" is the result of observing or measuring the time popcorn kernels require to pop. In this context, the sentence best matches the word "observation" which the term used in the Scientific method to refer to statements that are the result of studying a phenomenon, either through the senses such as sight or through precise instruments that allow scientists to understand numerically variables such as time, speed, temperature, etc.

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A concise definition of pair production
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4 years ago
How much potassium nitrate, KNO3, would completely dissolve in 100g of water at 40℃?
const2013 [10]
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8 0
3 years ago
In the periodic table of elements, what do all of the elements in group 2 have in common?
Shkiper50 [21]
The correct answer is letter C.
6 0
3 years ago
Read 2 more answers
The c-cl bond dissociation energy in cf3cl is 339 kj/mol. What is the maximum wavelength of photons that can rupture this bond?
ruslelena [56]

Answer:

3.53*10^{-7} m

Explanation:

Photon that can rupture the bonds are those with the energy of the bond dissociation energy. If we want to know the energy for each molecule we have to take into account that:

1mol=6.022*10^{23}molecule

Hence, we have

E_d=339\frac{10^{3}J}{mol}*\frac{1mol}{6-022*10^{23}molecules}=5.62*10^{-19}J/molecule

but the energy is also:

E_d=h\nu =\frac{hc}{\lambda}\\\\\lambda=\frac{hc}{E_d}

where h is the Planck's constant and c is the speed of ligth. By replacing we obtain:

\lambda=\frac{(6.62*10^{-34}Js)(3*10^{8}m/s)}{5.62*10^{-19}J}=3.53*10^{-7}m

hope this helps!

7 0
3 years ago
Read 2 more answers
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