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Svetlanka [38]
3 years ago
10

An electromagnet is a solenoid with a piece of ferromagnetic material within it.

Physics
1 answer:
Vlada [557]3 years ago
3 0
ANSWER:
The answer will be OT
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D
Ber [7]

Answer:

D

Explanation:

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3 0
2 years ago
Read 2 more answers
In a circus act, a 70 kg clown is shot from a cannon with an initial velocity of 17 m/s at some unknown angle above the horizont
EleoNora [17]

Answer:

K_{2}=7302.4J

Explanation:

Given the initial velocity of the clown, his mass and final height we can calculate the final kinetic energy using the <em><u>conservation of total mechanical energy</u></em>

K_{1}+U_{1}=K_{2}+U_{2}

K_{2}=K_{1}+U_{1}-U_{2}

K_{2}=\frac{1}{2}mv_{1}^{2}+mgh_{1}-mgh_{2}

Since h_{1}=0

K_{2}=\frac{1}{2}mv_{1}^{2}-mgh_{2}

K_{2}=\frac{1}{2}(70kg)(17m/s)^2-(70kg)(9.8m/s^2)(4.1m)=7302.4J

K_{2}=7302.4J

7 0
3 years ago
Ben and tom lifted plates up and down to practice for work. it is true or false that work has been. Accomplished
Orlov [11]

Explanation:

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6 0
3 years ago
Which of the following is an abiotic limiting factor for a plant population in an ecosystem?
Ludmilka [50]

Correct answer is Availability of soil minerals.

There are two types of limiting factors that affect plant population in a ecosystem. They are:

  1. Biotic
  2. Abiotic

Biotic factors includes food, diseases etc. Such as Invasive weed species, seed dispersal by wind, disease-causing fungal spores are examples of biotic limiting factor.

Abiotic factors include sunlight, temperature and chemical environment. The availability of soil mineral is an example of abiotic limiting factor. Growth of plant population depends on availability of soil minerals.

8 0
2 years ago
In designing a backyard water fountain, a gardener wants to stream of water to exit from the bottom of one tub and land in a sec
mote1985 [20]

To solve this problem it is necessary to apply the concepts related to the kinematic equations of movement description.

From the definition we know that the speed of a body can be described as a function of gravity and height

V = \sqrt{2gh}

V = \sqrt{2*9.8*0.15}

V = 1.714m/s

Then applying the kinematic equation of displacement, the height can be written as

H = \frac{1}{2}gt^2

Re-arrange to find t,

t = \sqrt{2\frac{h}{g}}

t = \sqrt{2\frac{0.5}{9.8}}

t = 0.3194s

Thus the calculation of the displacement would be subject to

x = vt

x =1.714*0.3194

x = 0.547m

Therefore the required distance must be 0.547m

4 0
3 years ago
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