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alina1380 [7]
3 years ago
5

PLEASE HELP.. I WOULD BE SO HAPPY!! ILL MAKE YOLO THE BRAINLIEST....

Physics
1 answer:
madreJ [45]3 years ago
6 0

Answer:

YOLOOOoo

Explanation:

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A student takes a ride on a ferris wheel and goes around 5 times. if the radius of the ferris wheel is 7.5 m how far did the stu
poizon [28]

If the radius is 7.5 meters, then the circumference would be 47.1239. That times five is 235.6195

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3 years ago
What net force acting on a 14 KG wagon produces an acceleration of 1.5 MS^2?
valentina_108 [34]

21N

Explanation:

Given parameters:

Mass of wagon = 14kg

Acceleration = 1.5m/s²

Unknown:

Net force on wagon = ?

Solution:

Force is a pull or push on a body that causes a body to change its state. It is expressed as:  

                 Force = mass  x acceleration

  Force on wagon = 14 x 1.5 = 21N

Learn more:

Force brainly.com/question/10470406

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3 years ago
A yo-yo is made of two solid cylindrical disks, each of mass 0.055 kg and diameter 0.070 m , joined by a (concentric) thin solid
DedPeter [7]

Answer: IM 95%sure that the answer is B jus took the test got the answer right

Explanation:

6 0
3 years ago
Read 2 more answers
A construction worker is carrying a load of 40 kg over his head and is walking at a constant velocity if he travels a distance o
Anastasy [175]

Answer:

W = 0

Explanation:

We are given with, a construction worker is carrying a load of 40 kg over his head and is walking at a constant velocity. He travels a distance of 50 m.

The work done by an object is given by :

W=Fd

F = ma

So,

W=mad

m is mass

a is acceleration

d is displacement

The worker is moving with constant velocity, its acceleration will be 0. So, the work done by the worker is 0.

8 0
3 years ago
A -3.00 nc point charge is at the origin, and a second -5.50 nc point charge is on the x-axis at x = 0.800 m. find the electric
Liula [17]

The electric field produced by a single-point charge is given by

E(r)=k\frac{q}{r^2}

where

k is the Coulomb's constant

q is the charge

r is the distance from the charge


To find the electric field at x=0.200 m, we need to find the electric field produced by each charge at that point, and then find their resultant.


1) The first charge is q=-3.00 nC=-3.00 \cdot 10^{-9} C, and it is located at x=0, so its distance from the point x=0.200 m is

r=0.200 m-0=0.2 m

Therefore, the electric field is

E_1=(8.99 \cdot 10^9 Nm^2C^{-2})\frac{(3.0 \cdot 10^{-9} C)}{(0.2 m)^2}=675 N/C

And since the charge is negative, the direction of the field is toward the charge, so toward negative x direction.


2) The second charge is q=-5.50 nC=-5.5 \cdot 10^{-9}C and it is located at x=0.800 m, so its distance from the point is

r=0.800 m-0.200 m=0.6 m

Therefore, the electric field is

E_2 = (8.99 \cdot 10^9 Nm^2C^{-2})\frac{(5.5 \cdot 10^{-9} C)}{(0.6 m)^2}=137.5 N

And since the charge is negative, the direction of the field is toward the charge, so toward positive x-direction.


3) The total electric field at x=0.200 m will be given by the difference between the two fields (because they are in opposite directions). Taking the x-positive direction as positive direction, we have

E=E_2 -E_1 =137.5 N/C/C-675 N/C=-537.5 N/C

and the sign tells us that the field is directed toward negative x-direction.

7 0
3 years ago
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