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maw [93]
3 years ago
13

HELPPPP

Physics
1 answer:
PSYCHO15rus [73]3 years ago
8 0
That’s kinda messed up ⬆️
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Black holes are highly condensed remnants of stars. Some black holes, together with a normal star, form binary systems. In such
borishaifa [10]

\lambda_\text{max} = 2.63\times 10^{-9}\;\text{m}.

<h3>Explanation</h3>

The peak emission wavelength of an object depends on its absolute temperature.

\lambda_\text{max} = \dfrac{2.90\times 10^{-3}}{T},

where

  • \lambda_\text{max} is the wavelength in meters where the emission is the strongest.
  • T is the temperature of the object in degrees Kelvins.

For the gas falling into the black hole,

T = 1.10\times 10^{6}\;\text{K}.

Apply the formula:

\lambda_\text{max} = \dfrac{2.90\times 10^{-3}}{T} = \dfrac{2.90\times 10^{-3}}{1.10\times 10^{6}} = 2.64\times 10^{-9}\;\text{m} = 2.64 \;\text{nm}.

The question mentioned that \lambda_\text{max} is in the X-ray region of the electromagnetic spectrum. According to Encyclopedia Britannica, the wavelength of X-rays range from 10^{-8}\;\text{m}=10\;\text{nm} to 10^{-10}\;\text{m} = 0.1\;\text{nm}, which indeed includes 2.64\times 10^{-9}\;\text{m} = 2.64 \;\text{nm}.

4 0
3 years ago
Use your periodic table to answer the following question.
Pavel [41]
Helium has only 2 electrons in it's valence shell

So, option D is your answer.

Hope this helps!
6 0
3 years ago
Beating a carpet with a carpet beater.
prisoha [69]
I would say a short person with muscles considering they are closer to the ground, but they may not be able to build up as much force in such a short time compared to the tall person.
8 0
3 years ago
Why do baseball pitchers throw the ball at an angle that is slightly above the horizontal if they want the ball to reach at appr
lesantik [10]

Answer:

The angle above the horizontal at which the pitcher throws the ball determines the distance the ball travels before returning to the height at which it was thrown

Explanation:

The baseball is thrown as a projectile and the range, 'R', of the baseball which is the distance the baseball travels before the height above the ground returns to the initial height  is given given as follows;

R = \dfrac{u^2 \cdot sin(2\cdot \theta )}{g}

Where;

R = The range of the baseball = The horizontal distance away from the pitcher the ball reaches

u = The initial velocity with which the baseball was thrown

θ = The angle above horizontal a baseball pitcher throws the ball

g = The acceleration due to gravity ≈ 9.81 m/s²

From the the equation, when θ = 0, sin(θ) = sin(0) = 0 and the ball does not cover any horizontal distance before going lower than the height at which it was thrown, therefore, for the ball to travel further, the angle of launch, θ has to be larger than 0.

4 0
3 years ago
Why do alpha particles and nuclei repel each other rather than attract eachother
Vesnalui [34]
Both have positive charge. In fact, an alpha particle IS a nucleus of a Helium atom.
5 0
3 years ago
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