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pentagon [3]
2 years ago
14

A race car goes forward from 0 to a velocity of 80 m/s in 9.4 s. What is its acceleration?

Physics
1 answer:
Helen [10]2 years ago
6 0

Answer:

The average acceleration is about 8.51 m/s

Explanation:

     We can use the formula for acceleration to solve.

a = \frac{velocity_{final} -velocity_{start} }{time}

a =  \frac{80-0}{9.4}

a =  \frac{80}{9.4}

a ≈ 8.51

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Pressure __________ with depth to support the fluid weight above
eduard

Answer:Hydrostatic

Explanation: I think this is the answer, not sure. Sorry

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3 years ago
A soccer player takes a corner kick, lofting a stationary ball 33.0° above the horizon at 15.0 m/s. If the soccer ball has a mas
Alexxandr [17]

Explanation:

It is given that,

Mass of the soccer ball, m = 0.425 kg

Speed of the ball, u = 15 m/s

Angle with horizontal, \theta=33^{\circ}

Time for which the player's foot is in contact with it, \Delta t = 5.1\times 10^{-2}\ s

Part A,

The x component of the soccer ball's change in momentum is given by :

\Delta p_x=mv\ cos\theta

\Delta p_x=0.425\times 15\ cos(33)

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The y component of the soccer ball's change in momentum is given by :

\Delta p_y=mv\ sin\theta

\Delta p_y=0.425\times 15\ sin(33)

p_y=3.47\ kg-m/s

Hence, this is the required solution.

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3 years ago
List things in your house and put them in order of density
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3 years ago
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The distance between two electric pole is 800m then express this in terms of mm​
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An 20-cm-long bicycle crank arm, with a pedal at one end, is attached to a 25-cm-diameter sprocket, the toothed disk around whic
Andrej [43]

Answer:

0.033815 m/s²

12.48810875 m

Explanation:

t = Time taken = 12 s

\omega_f = Final angular velocity = 95 rpm

\omega_i = Initial angular velocity = 64 rpm

\alpha = Angular acceleration

\theta = Angle of rotation

\omega_f=\omega_i+\alpha t\\\Rightarrow \alpha=\frac{\omega_f-\omega_i}{t}\\\Rightarrow \alpha=\frac{95\times \frac{2\pi}{60}-64\times \frac{2\pi}{60}}{12}\\\Rightarrow \alpha=0.27052\ rad/s^2

Tangential acceleration is given by

a_t=\alpha r\\\Rightarrow a_t=0.27052\times 0.125\\\Rightarrow a_t=0.033815\ m/s^2

The tangential acceleration of the pedal is 0.033815 m/s²

\omega_f^2-\omega_i^2=2\alpha \theta\\\Rightarrow \theta=\frac{\omega_f^2-\omega_i^2^2}{2\alpha}\\\Rightarrow \theta=\frac{\left(95\times\frac{2\pi }{60}\right)^2-\left(64\times\frac{2\pi}{60}\right)^2}{2\times 0.27052}\\\Rightarrow \theta=99.90487\ rad

Linear displacement would be 99.90487\times \frac{1}{2\pi}\times 2\pi\times 0.125=12.48810875\ m

Length of chain that passes in the interval is 12.48810875 m

4 0
3 years ago
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