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ElenaW [278]
3 years ago
6

What are the zeros of the quadratic function f(x) 128² - 10x - 3?

Mathematics
2 answers:
rusak2 [61]3 years ago
8 0
I love youuuuuuuuuuu
Temka [501]3 years ago
4 0

Answer:

When 2x^2 - 10x - 3 is plugged into the quadratic equation, the resulting zeroes are x = (5 + sqrt(31))/2 and (5 - sqrt(31))/2. Hope this helps!

Step-by-step explanation:

  • <em>If my answer is incorrect, please correct me! </em>
  • <em>If you like my answer and explanation, mark me as brainliest!</em>

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Someone please helppp.!
Sever21 [200]

Answer:

C

Step-by-step explanation:

4 0
3 years ago
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Which of the following describes a rectangular prism?
Allushta [10]

Answer:

D. a shape with six faces where all six faces are identical

3 0
3 years ago
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John has dimes and quarters worth $4.50. He has four more quarters than dimes. How many coins of
N76 [4]

Answer:

10 dimes and 14 quarters

Step-by-step explanation:

take the amount of four quarters to start with: 1$

then from here, for add one quarter and one dimes worth: 35 c

keep adding until you reach 450

then count how many 35 c you counted and thats how many dimes you have

add four to that number and youll get the amount of quarters

5 0
2 years ago
Could someone please help on this question? I’m giving 20 points and brainliest but I need it quickly so please help!
AnnZ [28]
<h3>Answer:  HF = 5</h3>

=============================================

Explanation:

Refer to the diagram below. I'm adding in points A and B, which are marked in blue. I'm also adding in variables x, y, and z.

The goal is to find HF, so let's make that equal to x. This is also equal to HB because they are radii of the same circle.

Let y be the length of segments JA and JB.

Let z be the length of segments CF and CA.

So in short we have

  • x = HF = HB
  • y = JA = JB
  • z = CF = CA

We know that

  • CH = 13
  • HJ = 19
  • CJ = 22

This must mean

  • CH = CF+HF = z+x = 13
  • HJ = HB+JB = x+y = 19
  • CJ = CA+JA = z+y = 22

Or in short,

  • z+x = 13
  • x+y = 19
  • z+y = 22

Let's solve the first equation for z to get z = -x+13. I subtracted x from both sides.

Now plug this into the third equation to get

z+y = 22

(z) + y = 22

(-x+13) + y = 22 ... replace z with -x+13

-x+13+y = 22

-x+y+13 = 22

-x+y = 22-13 .... subtract 13 from both sides

-x+y = 9

------------------------------------

So we have this reduced system of equations of two variables and two equations

  • x+y = 19 ... found earlier
  • -x+y = 9 .... what we just found above

Add the equations straight down. This is the elimination property.

Doing so leads to the x terms canceling out since x + (-x) = 0x = 0

The y terms add to y+y = 2y

The terms on the right hand side add to 19+9 = 28

We are left with 2y = 28 which solves to y = 28/2 = 14.

If y = 14, then,

x+y = 19

x+14 = 19

x = 19-14

x  = 5

In which we can then say

z = -x+13

z = -5+13

z = 8

Though we don't need to find z (unless you're curious about it).

Since x = 5, and we set HF equal to x, this means that HF = 5.

6 0
3 years ago
F(x)=-2x-1 and g(x)=x^2-1. Find (fog)(-5).
serg [7]

Answer: - 49

Step-by-step explanation:

f(x) = -2x - 1

g(x) = x^{2} - 1

fg(x) = f (x^{2} - 1) , we just put in the value of g(x) , the next thing is to substitute x^{2} - 1 for the value of x in f(x) , that is

fg(x) = -2(x^{2} - 1) - 1

fg(x) = -2x^{2} + 2 - 1

fg(x) = -2x^{2} + 1

Therefore : fg(-5) means we will substitute -5 for x in fg(x) , that is

fg(-5) = -2 ((-5)^{2} + 1

fg(-5) =  -2(25) + 1

fg(-5) = -50 + 1

fg(-5) = -49

7 0
3 years ago
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