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3 years ago

What are the zeros of the quadratic function f(x) 128² - 10x - 3?

Mathematics

2 answers:

rusak2 [61]3 years ago

8 0

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Temka [501]3 years ago

4 0

Answer:

When 2x^2 - 10x - 3 is plugged into the quadratic equation, the resulting zeroes are x = (5 + sqrt(31))/2 and (5 - sqrt(31))/2. Hope this helps!

Step-by-step explanation:

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Whats the answer for number 13?

Mumz [18]

Answer: option 3

Step-by-step explanation:

so you would do

-2=3(1)-5

-2=3-5

-2=-2

3 0

2 years ago

2[5x+3]-2=14 what are the solutions

sertanlavr [38]

The answer for this problem is x=1

4 0

3 years ago

You observe a portfolio for five years and determine that its average annual return is 13% and the standard deviation of its ret

horrorfan [7]

Answer:

There is a 95% probability that the portfolio would not loose more than 30% of its value.

Step-by-step explanation:

The confidence interval for proportions (<em>p</em>) is:

$CI=\hat p\pm z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}$

The information provided is:

$\hat p = 0.13\\\sqrt{\frac{\hat p(1-\hat p}{n}} =0.21$

For 95% confidence level the critical value of <em>z</em> is:

$z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96$

The 95% confidence interval for average annual return is:

$CI=\hat p\pm z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}\\=0.13\pm 1.96\times0.21\\=0.13\pm 0.4116\\=(-0.2816, 0.5416)\\\approx(-28\%, 54\%)$

The lower limit of the 95% confidence interval is -28%.

This implies that the portfolio would not loose more than 28% of its value.

Thus, there is a 95% probability that the portfolio would not loose more than 30% of its value.

6 0

3 years ago

How many different ways are there to choose a dozen donuts from the 4 varities at a donut shop so that you get atleast one donut

Leno4ka [110]

There are 330 different ways for choosing a dozen donuts from the 4 varieties at a donut shop. (at least one donut of every variety must be selected)

<h3>How to calculate the number of ways to select items?</h3>

There are 'r' items from 'n' different varieties (repetition allowed). Then, the number of ways to select items is given by

The number of ways = $_{n+r-1}C_r$

Where the combination $_{n}C_r$ is calculated as

$_{n}C_r=\frac{n!}{r!(n-r)!}$

<h3 /><h3>Calculation:</h3>

It is given that there are 4 varieties of donuts in a shop. I.e., n = 4

Number of donuts to be selected r = 12 (one dozen)

And also given that at least one donut of every variety has to be selected.

Since there are 4 varieties, at least one from each of these means the count is 4.

So, the remaining number of donuts to be selected is 12 - 4 = 8.

So, r becomes 8 i.e., r = 8

On substituting,

the number of ways of selecting the remaining 8 donuts = $_{4+8-1}C_4$

⇒ $_{11}C_4$

⇒ $\frac{11!}{4!(11-4)!}$

⇒ $\frac{11!}{(4!)(7!)}$

⇒ 330

Therefore, there are 330 different ways for choosing a dozen donuts from the 4 varieties at a donut shop.

Learn more about combinations here:

brainly.com/question/11732255

#SPJ4

5 0

2 years ago

Which graph represents the solution to this inequality?<br> 16x - 80x < 37 + 27 DS<br> (2 points)

Naddika [18.5K]

Graph 2 graph b is the answer

6 0

3 years ago