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Romashka [77]
4 years ago
5

In the auditory system, the unit for measuring the amplitude of sound is _____.

Physics
2 answers:
nasty-shy [4]4 years ago
6 0
B decibel is the answer

natta225 [31]4 years ago
6 0
Hello there,

<span>In the auditory system, the unit for measuring the amplitude of sound is _____.
</span>
Answer: decibel.

Hope This Helps You!
Good Luck Studying :)
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Zero, a hypothetical planet, has a mass of 5.3 x 1023 kg, a radius of 3.3 x 106 m, and no atmosphere. A 10 kg space probe is to
Andrej [43]

(a) 3.1\cdot 10^7 J

The total mechanical energy of the space probe must be constant, so we can write:

E_i = E_f\\K_i + U_i = K_f + U_f (1)

where

K_i is the kinetic energy at the surface, when the probe is launched

U_i is the gravitational potential energy at the surface

K_f is the final kinetic energy of the probe

U_i is the final gravitational potential energy

Here we have

K_i = 5.0 \cdot 10^7 J

at the surface, R=3.3\cdot 10^6 m (radius of the planet), M=5.3\cdot 10^{23}kg (mass of the planet) and m=10 kg (mass of the probe), so the initial gravitational potential energy is

U_i=-G\frac{mM}{R}=-(6.67\cdot 10^{-11})\frac{(10 kg)(5.3\cdot 10^{23}kg)}{3.3\cdot 10^6 m}=-1.07\cdot 10^8 J

At the final point, the distance of the probe from the centre of Zero is

r=4.0\cdot 10^6 m

so the final potential energy is

U_f=-G\frac{mM}{r}=-(6.67\cdot 10^{-11})\frac{(10 kg)(5.3\cdot 10^{23}kg)}{4.0\cdot 10^6 m}=-8.8\cdot 10^7 J

So now we can use eq.(1) to find the final kinetic energy:

K_f = K_i + U_i - U_f = 5.0\cdot 10^7 J+(-1.07\cdot 10^8 J)-(-8.8\cdot 10^7 J)=3.1\cdot 10^7 J

(b) 6.3\cdot 10^7 J

The probe reaches a maximum distance of

r=8.0\cdot 10^6 m

which means that at that point, the kinetic energy is zero: (the probe speed has become zero):

K_f = 0

At that point, the gravitational potential energy is

U_f=-G\frac{mM}{r}=-(6.67\cdot 10^{-11})\frac{(10 kg)(5.3\cdot 10^{23}kg)}{8.0\cdot 10^6 m}=-4.4\cdot 10^7 J

So now we can use eq.(1) to find the initial kinetic energy:

K_i = K_f + U_f - U_i = 0+(-4.4\cdot 10^7 J)-(-1.07\cdot 10^8 J)=6.3\cdot 10^7 J

3 0
3 years ago
At what distance from the centre of the earth its acceleration due to gravity becomes one third only? [Mass and radius of earth
Kipish [7]

Answer:

235

Explanation:

3 0
3 years ago
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A guitar string is plucked. What best describes the formation and transmission of the sound wave?
makvit [3.9K]

The string vibrates the surrounding air, which produces a longitudinal wave.

Brainly if correct? Please and thank you :D

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3 years ago
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In a church choir loft, two parallel walls are 5.30 m apart. The singers stand against the north wall. The organist faces the so
morpeh [17]

The virtual image is as far behind the mirror as the choir is in front of the mirror. Thus, the image is 5.30 m behind the mirror. The image of the choir is 0.800 m+ 5.30 m= 6.10 m from the organist.

<u>Using</u><u> similar triangles</u><u>:</u>

h'/0.600 = 6.10/0.800

So, h' = 0.600( 6.10/0.800 ) = 4.58m

<h3><u>The concept of Ray Optics and Optical Instrument</u></h3>

A subject of physics called Ray Optics and Optical Instruments investigates the characteristics and behavior of light. When light moves in a straight line, as in ray optics, also known as geometrical optics, it is said that every object has an image. The optical tools that are now in use make use of the reflecting and refracting qualities of mirrors, lenses, and prisms.

<h3><u>What is ray optics ?</u></h3>

The theory of ray optics, often known as geometrical optics, describes how light travels in terms of rays. It discusses how light behaves. Typically, light is thought of as a beam that follows a straight path.

The behavior of infrared, ultraviolet, and visible light is explained by the science of optics. Ray is the name given to the route that light takes. A beam of light is another name for a collection of light rays.

To view more on the Ray Optics and Optical Instrument, refer to:

brainly.com/question/19866597

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7 0
2 years ago
Learning Goal: To practice Problem-Solving Strategy 15.1 Mechanical Waves. Waves on a string are described by the following gene
kaheart [24]

Answer:

so the transverse displacement is  0.089963 m

Explanation:

Given data

equation y(x,t)=Acos(kx−ωt)

speed  v = 9.00 m/s

amplitude A = 9.00 × 10^−2 m

wavelength λ   = 0.480 m

to find out

the transverse displacement

solution

we know

v = angular frequency / wave number

and

wave number = 2 \pi / λ  =  2 \pi / 0.480  = 13.0899 m^{-2}

angular frequency = v k

angular frequency = 9.00 × 13.0899

angular frequency = 117.8097 rad/sec = 118 rad/sec

so

equation y(x,t)=Acos(kx−ωt)

y(x,t)=9.00 × 10^−2 cos(13.0899 x−118t)

when x =0 and and t = 0

maximum y(x,t)= 9.00 × 10^−2 cos(13.0899 (0) − 118 (0))

maximum y(x,t)= 9.00 × 10^−2  m

and when x =  x = 1.59 m and t = 0.150 s

y(x,t)=9.00 × 10^−2 cos(13.0899 (1.59) −118(0.150) )

y(x,t)=9.00 × 10^−2 × (0.99959)

y(x,t) = 0.089963 m

so the transverse displacement is  0.089963 m

5 0
3 years ago
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