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rewona [7]
2 years ago
7

si el calor fuese un fluido ¿en algun momento se agotaria después de que dos objetos se frotaran mutuamente?​

Chemistry
1 answer:
rjkz [21]2 years ago
8 0

Si el calor fuese un fluido no se agotaría, solamente cambiaría su forma o localización.

<h3>¿Qué ocurre cuando dos objetos con diferente temperatura están en contacto?</h3>

Cuando dos objetos de diferente temperatura están en contacto el calor fluye del objeto con mayor temperatura o más caliente, al objeto con menor temperatura o más frío. Esto ocurre hasta que ambos objetos alcanzan la misma temperatura.

<h3>¿Qué sucede con el calor?</h3>

El calor o energía termina se disipa hacia el entorno o la atmosfera cuando un cuerpo se enfría o hacia otro cuerpo si hay transferencia de calor, sin embargo, el calor no desaparece debido a la ley de la conservación de la energía y materia.

<h3>¿Qué sucedería si el calor fuera un fluido?</h3>

Si el calor fuera un fluido este fluido no desaparecería ni se agotaría, solamente se podría disipar a la atmósfera o ambiente.

Aprenda más sobre calor en: brainly.com/question/15890992

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What are valence electrons and how do they affect the properties of an atom?
vlada-n [284]

The term "valence electrons" refers to all of the electrons in an atom's outermost shell.

The centre of the atom is where the nucleus is. The nucleus contains protons and neutrons. The electrons travel in a specific circular direction and at a specific distance from the nucleus.

The atom's final shell's electrons take part in chemical reactions and the production of bonds. Both ionic and covalent bonding involve valence electrons. Metals are elements with one, two, or three electrons in their final shell.

These substances become positive ions after losing their electrons. Non-metals are substances with 5, 6, or 7 electrons in the outermost shell. These substances all gain electrons and change into negative ions.

Ionic bonds are those created by the transfer of electrons between metals and non-metals. For instance, ionic bonding allows sodium and chlorine to interact to generate sodium chloride.

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4 0
1 year ago
molecules with a plane of symmetry between the chiral centers are achiral and meso. identify which of the following molecules ar
maks197457 [2]

Molecules with a plane of symmetry between the chiral centers are achiral and meso. From the given molecules (Picture attached) only (A) compound 1 is meso.

When compounds possess a plane of symmetry between the chiral centers they are called achiral or meso compounds. Among the given compounds (A) compound 1 have a plane of symmetry. So we can say compound one is a meso or achiral compound. Compounds two, three, and four have no plane of symmetry, as you can see in the structures attached. So all other compounds (compound 2, compound 3, and compound 4) except compound one are not meso or achiral.

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7 0
1 year ago
11-Draw a pedigree chart for 2 parents and 4 offsprings,
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4 0
3 years ago
What is the wavelength of infrared radiation with a frequency of 3.85 x 10^12 Hz?
ELEN [110]

Answer:

Wavelenght is 7,79x10⁻⁵ m

Explanation:

The equation that connects wavelentgh (λ) and frequency (ν) is:

λ=c/ν

Where c is speed of light (3x10⁸ m/sec) and λ is expressed in lenght´s units and ν is expressed in "time⁻¹ " units (for example, sec⁻¹)

According to the details, if we just replace the given value of frequency, we just obtaing wavelenght data:

λ= (3x10⁸ m/sec)/(3,85x10¹² sec⁻¹) = 7,79x10⁻⁵ m

3 0
3 years ago
Imagine that you have a 5.00 L gas tank and a 3.50 L gas tank. You need to fill one tank with oxygen and the other with acetylen
Lorico [155]

Answer:

77.14 atm of pressure should be of an acetylene in the tank.

Explanation:

2C_2H_2+5O_2\rightarrow 4CO_2+2H_2O

According to reaction, 2 moles of acetylene reacts with 5 moles of oxygen.

Moles of oxygen=n_1

Moles of acetylene =n_2

\frac{n_1}{n_2}=\frac{5 mol}{2 mol}=\frac{5}{2}

Volume of large tank with oxygen gas, V_1 = 5.00 L

Pressure of the oxygen gas inside the tank = P_1=135 atm

RT=\frac{P_1V_1}{n_1} ..[1]

Volume of small tank with acetylene gas ,V_2= 3.50 L

Pressure of the acetylene gas inside the tank = P_2=?

RT=\frac{P_2V_1}{n_2} ..[2]

Considering both the gases having same temperature T, [1]=[2]

\frac{P_1V_1}{n_1}=\frac{P_2V_2}{n_2}

P_2=\frac{P_1V_1\times n_2}{V_2\times n_1}

=\frac{135 atm\times 5.00 L\times 2}{3.50 L\times 5}=77.14 atm

77.14 atm of pressure should be of an acetylene in the tank.

8 0
3 years ago
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