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Elenna [48]
2 years ago
11

Which of the following is the best definition of ethics?

Chemistry
1 answer:
Andrej [43]2 years ago
4 0

Answer:

C

Explanation:

I believe the answer is C.

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A 1.2 kg sample of Th-228 has a half-life of 1.9 years. How many grams of Th is left after 13.3 years?
Bumek [7]
.009375 kg or 9.375 grams will remain
7 0
3 years ago
Predict how the addition of a catalyst would affect the rate of the reaction below, and explain your prediction H2 (g) + I2 (g)
Fynjy0 [20]
A catalyst is a chemical substance that hastens the chemical reaction. This does not participates in the creating the product(s) but allows it to be formed easily. With this, it is now known that the rate of the reaction becomes relatively higher compared to the uncatalyzed reactions.

Therefore, the answer to this item is the rate of the reaction becomes faster. 
4 0
2 years ago
Read 2 more answers
Can someone help with this please?
Aleks04 [339]
I think the answer would be yes. if my math is correct 84,596 divided by 29 equals 2,917 sickles. 2,917 sickles is equal to 172 galleon. therefore he would have enough to buy the 70 galleon broomstick. hopefully i did this right and it helped!
4 0
2 years ago
How many moles of oxygen are needed for the complete combustion of 29.2 grams of acetylene?
podryga [215]

Moles of Oxygen= 2.8075 moles

<h3>Further explanation</h3>

Given

29.2 grams of acetylene

Required

moles of Oxygen

Solution

Reaction(Combustion of Acetylene) :

2 C₂H₂ (g) + 5 O₂ (g) ⇒ 4CO₂ (g) + 2H₂O (g)

Mol of Acetylene :

= mass : MW Acetylene

= 29.2 g : 26 g/mol

= 1.123

From equation, mol ratio of Acetylene(C₂H₂) : O₂ = 2 : 5, so mol O₂ :

= 5/2 x mol C₂H₂

= 5/2 x 1.123

= 2.8075 moles

7 0
2 years ago
What is the enthalpy of combustion (per mole) of C4H10 (g)? 
Artemon [7]
The balanced chemical reaction for the complete combustion of C4H10 is shown below:

                    C4H10 + (3/2)O2 --> 4CO2 + 5H2O

The enthalpy of formation are listed below:
          C4H10: -2876.9 kJ/mol
              O2:   none (because it is pure substance)
             CO2: -393.5 kJ/mol
             H2O: -285.8 kJ/mol

The enthalpy of combustion is computed by subtracting the total enthalpy formation of the reactants from that of the products.

               ΔHc = (4)(-393.5 kJ/mol) + (5)(-285.8 kJ/mol) - (-2876.9 kJ/mol)
                       = -<em>126.1 kJ</em>

Thus, the enthalpy of combustion of the carbon is -126.1 kJ. 
5 0
2 years ago
Read 2 more answers
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