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Ivanshal [37]
3 years ago
9

To increase friction you could

Physics
1 answer:
Rainbow [258]3 years ago
4 0
You could make the two rubbing thingers come closer together.
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How long does it take for an obituary to appear?
Licemer1 [7]
24hours is the correct answer
6 0
3 years ago
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the distance between any two bodies is 10 M and the gravitational force between them is 3.2×10-⁹m. if the mass of one object is
cluponka [151]

Answer:

0.8 x 10^-9 kg

Explanation:

Given,

Distance ( R ) = 10 m

Force ( F ) = 3.2 x 10^-9 N

Mass ( m1 ) = 40 kg

To find : Mass ( m2 ) = ?

Formula : -

F = m1.m2 / R^2

m2 = FR^2 / m1

= 3.2 x 10^-9 x 10 / 40

= 3.2 x 10^-9 / 4

= ( 3.2 / 4 ) x 10^-9

m2 = 0.8 x 10^-9 kg

3 0
3 years ago
Pls help my science teacher is a horrible teacher...
Anettt [7]

First of all, looks like your teacher is indeed pretty horrible. Secondly, the constraints to consider would be proper weight distribution, methods to minimize excessive motion of the building structure, and quantities such as volume and density, which would help in determining the optimal structure. Keeping the frequency of oscillation for a building low in case of an earthquake or natural disaster would also be a priority.

4 0
3 years ago
A rotating lens mechanism blocks the view of the object as the new lenses are rotated. Be sure to click each lense firmly into p
Jobisdone [24]

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6 0
2 years ago
A 10 kg box hangs from a rope. What is the tension in the rope (in Newtons) if the box is stationary
Archy [21]

Answer:

T = 98 N

Explanation:

The gravity of the earth is known to be 9.8 m/s²

Data:

  • m = 10 kg
  • g = 9.8 m/s²
  • T = ?

Use formula:

  • \boxed{\bold{T=m*g}}

Replace and solve:

  • \boxed{\bold{T=10\ kg*9.8\frac{m}{s^{2}}}}
  • \boxed{\boxed{\bold{T=98\ N}}}

The tension in the rope is <u>98 Newtons.</u>

Greetings.

5 0
2 years ago
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