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Vadim26 [7]
2 years ago
8

If the ball that is thrown downward has an acceleration of magnitude aaa at the instant of its release (i.e., when there is no l

onger any force on the ball due to the woman's hand), what is the relationship between aaa and ggg, the magnitude of the acceleration of gravity
Physics
1 answer:
kakasveta [241]2 years ago
5 0

Explanation:

At the instant of release there is no force but an acceleration of a, this means the ball is falling freely under the force of gravity. Then the acceleration would be due to force of gravity and acceleration a = g =9.81 m/s^2.

g= acceleration due to gravity

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A 24kg child descends a slide 5m high and reaches the bottom with a speed of 2.8m/s. How much thermal energy due to friction was
Rama09 [41]

Answer:

1101.96 J

Explanation:

Potential energy at top = mgh = 24*10*5 = 1200J

Kinetic energy at bottom = 1/2*m*v² = 0.5*24*(2.8)²= 94.08 J

Loss of energy = 1200 J - 98.04 J

                         = 1101.96 J

Thermal energy due to friction =1101.96 J

8 0
3 years ago
A student at the top of building of height h throws one ball upward with the initial speed V and then throws a second ball downw
Vlad1618 [11]

Answer:

They are the same (assuming there is no air friction)

Explanation:

Take a look at the picture.

When the first ball (the one thrown upward) gets to the point marked as A, the speed will has the exact same value V but the velocity will now point downward (just like the second ball).

So if you think about it, the first ball, from point A to the ground, will behave exactly like the second ball (same initial speed, same height).

That is why the speeds will be the same when they reach the ground.

7 0
3 years ago
Read 2 more answers
What is the wavelength of a sound wave traveling at 360 m/s and a
3241004551 [841]

Answer:2.4m

Explanation:

Velocity=360m/s

Frequency=150Hz

Wavelength=velocity ➗ frequency

Wavelength=360 ➗ 150

Wavelength=2.4m

8 0
3 years ago
PLEASE ANSWER NEED HELP!!!!!!!! PLEASE THE CORRECT ANSWER!!!!!!
Leya [2.2K]

Answer:

c

Explanation:

5 0
2 years ago
Two parallel plates have equal and opposite charges. When the space between the plates is evacuated, the electric field is E= 3.
svetlana [45]

Explanation:

The given data is as follows.

     Electric field between plates without dielectric, E_{1} = 3.50 \times 10^{5} V/m

   Electric field between the plates with dielectric, E_{2} = 2.40 \times 10^{5} V/m.

  Permittivity of free space, \epsilon_{o} = 8.85 \times 10^{-12} C^{2}/Nm^{2}

Now, we will determine the charge density as follows.

            \sigma_{i} = \epsilon_{o}(E_{1} - E_{2})

                 = 8.85 \times 10^{-12} \times (3.50 \times 10^{5} - 2.40 \times 10^{5})

                 = 9.735 \times 10^{-7} C/m^{2}

Thus, we can conclude that the charge density on each surface of the dielectric is 9.735 \times 10^{-7} C/m^{2}.

6 0
3 years ago
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