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Pie
3 years ago
7

When training to increase physical fitness, adaptation occurs....

Physics
2 answers:
weqwewe [10]3 years ago
5 0
Probably A it's not going to be easy or quick nor is it going to be short
user100 [1]3 years ago
3 0
I believe A.. training never gives instant results and is never a quick or short process !
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‼️‼️ Please help, urgent ‼️‼️ (check photo)
Alex787 [66]

Answer: The force constant k is 10600 kg/s^2

Step by step:

Use the law of energy conservation. When the elevator hits the spring, it has a certain kinetic and a potential energy. When the elevator reaches the point of still stand the kinetic and potential energies have been transformed to work performed by the elevator in the form of friction (brake clamp) and loading the spring.

Let us define the vertical height axis as having two points: h=2m at the point of elevator hitting the spring, and h=0m at the point of stopping.

The total energy at the point h=2m is:

E_{tot}=E_{kin}+E_{pot}\\E_{tot}= \frac{1}{2}mv^2+mg\Delta h = \frac{1}{2}2000 kg 4^2\frac{m^2}{s^2}+2000kg\, 9.8\frac{m}{s^2}2m=55200\,kg\frac{m^2}{s^2}

The total energy at the point h=0m is:

E_{tot}=E_{kin}+E_{pot}+Work=0+0+ Work\\E_{tot} =F_{friction}\Delta h+\frac{1}{2}k (\Delta h)^2=17000N\cdot 2m+\frac{1}{2}k\cdot 2^2 m^2

The two Energy values are to be equal (by law of energy conservation), which allows us to determine the only unknown, namely the force constant k:

17000N\cdot 2m+\frac{1}{2}k\cdot 2^2 m^2 = 55200 \,kg\frac{m^2}{s^2}\\k = \frac{55200-34000}{2}\,\frac{kg}{s^2}=10600\frac{kg}{s^2}

5 0
3 years ago
A boy is trying to roll a bowling ball up a hill, as shown in the image below. If
kherson [118]

The minimum initial velocity that the ball must have for it to reach the top of the hill is 21 m/s. The correct option is D.

<h3>What is mechanical energy?</h3>

The mechanical energy is the sum of kinetic energy and the potential energy of an object at any instant of time.

M.E = KE +PE

A boy is trying to roll a bowling ball up a hill. The friction is ignored.  The ball must have to reach the top of the hill with a velocity. The acceleration due to gravity, g = 9.8 m/s²

The conservation of energy principle states that total mechanical energy remains conserved in all situations where there is no external force acting on the system.

M.E bottom of hill = M.E on top of hill

Kinetic energy + Potential energy = Kinetic energy  + Potential energy

1/2 mu² + 0 =  0 + mgh

At the top of hill, the velocity will become zero. So, final kinetic energy is zero.

Substituting the values, we have

1/2 x u² = 9.8 x 22.5

u = sqrt [2 x9.8 x 22.5 ]

u= 21 m/s

Thus, the minimum initial velocity that the ball must have for it to reach the top of the hill is 21 m/s.

Learn more about mechanical energy.

brainly.com/question/13552918

#SPJ1

4 0
2 years ago
What is the relation between the weight of a body and acceleraton due to gravity?​
emmainna [20.7K]

Answer:

All objects on Earth, regardless of their mass, accelerate due to gravity at the same rate - that is, 9.8 m/sec2. The weight of an object can be calculated using the formula for force - F = m * a - where F equals the weight of the object and now the acceleration (a) is the acceleration of gravity (g).

6 0
3 years ago
What is the kinetic energy of a 7.56 kg bowling ball that is rolling at a speed of 2 m/s ?
postnew [5]

Answer:

K.E=?

Mass=7.56 kg

Velocity=2m/s

Solution::

K.E = 1/2mv^2

K.E=0.5*7.56*(2)^2

K.E= 0.5*7.56*4

K.E=15.12 joules.

7 0
3 years ago
. In a solid, particles do not move around each
nordsb [41]

Answer:

I am sure the awnser to this is

B. vibrate

8 0
3 years ago
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