Answer:
(A) 
(B) s = 146.664 m
Explanation:
We have given car starts from the rest so initial velocity u = 0 m /sec
Final velocity v = 88 km/hr
We know that 1 km = 1000 m
And 1 hour = 3600 sec
So 
Time is given t = 12 sec
(A) From first equation of motion v = u+at
So 

So acceleration of the car will be 
(b) From third equation of motion 
So 
s = 146.664 m
Distance traveled by the car in this interval will be 146.664 m
Answer:
the required revolution per hour is 28.6849
Explanation:
Given the data in the question;
we know that the expression for the linear acceleration in terms of angular velocity is;
= rω²
ω² =
/ r
ω = √(
/ r )
where r is the radius of the cylinder
ω is the angular velocity
given that; the centripetal acceleration equal to the acceleration of gravity a
= g = 9.8 m/s²
so, given that, diameter = 4.86 miles = 4.86 × 1609 = 7819.74 m
Radius r = Diameter / 2 = 7819.74 m / 2 = 3909.87 m
so we substitute
ω = √( 9.8 m/s² / 3909.87 m )
ω = √0.002506477 s²
ω = 0.0500647 ≈ 0.05 rad/s
we know that; 1 rad/s = 9.5493 revolution per minute
ω = 0.05 × 9.5493 RPM
ω = 0.478082 RPM
1 rpm = 60 rph
so
ω = 0.478082 × 60
ω = 28.6849 revolutions per hour
Therefore, the required revolution per hour is 28.6849
Answer:
the circles are called Sun spots. they are colder than the surrounding area.
Explanation:
Technology that does not harm the environment (environmental friendly technology)
Answer:
a. E(r) = 3.67 x 10⁴ N/C
b. E(r) = 5.38 x 10⁴ N/C
Explanation:
r1 = 8.83 cm
r2 = 15.4 cm
Charge on the inner shell = 5.03 x 10^-⁸ C
Charge on the outer shell = 2.77 x 10^-⁸ C
a) To find the electric field at r = 11.1 cm,
r₁ = 8.83 cm < r = 11.1 cm < r₂ = 15.4 cm
E(r) = <u>1 </u> <u>q₁ </u>
4
∈₀ r₂
E(r) = <u>( 8.99 x 10⁹ N.m²/C² ) ( 5.03 x 10⁻⁸)</u>
(0.111m)²
E(r) = 3.67 x 10⁴ N/C
b) To find the electric field at r = 36.1 cm
since r₁ < r₂ < r = 36.1 cm
E(r) = <u>1 </u> <u>q₁ ₊ q₂ </u>
4
∈₀ r₂
E(r) = <u>( 8.99 x 10⁹ N.m²/C² ) ( 5.03 + 2.77 )(1 x 10⁻⁸)</u>
(0.361m)²
E(r) = 5.38 x 10⁴ N/C