An object moves such that acceleration a(t)=2(1-3t). Given v(0)=-5 and x(0)=4, find x(1).
1 answer:
Answer:
x(1) = -1
Step-by-step explanation:
Given the equation for acceleration of the object as;
a(t)=2(1-3t)
a(t) = 2-6t
Integrate to get the velocity
v(t) = 2t-6t²/2 + C
v(t) = 2t-3t²+C
If v(0) = -5
when t = 0 v = -5
-5 = 2(0)-3(0)²+C
-5 = C
C = -5
v(t) = 2t-3t²-5
To get the displacement x(t), we will integrate the velocity function
x(t) = 2t²/2-3t³/3-5t+C
x(t) = t²-t³-5t+C
If x(0) = 4
At t = 0, x(t) = 4
4 = 0²-0³-5(0)+C
4 = C
C = 4
x(t) = t²-t³-5t+4
Get x(1)
x(1) = 1²-1³-5(1)+4
x(1) = 1-1-5+4
x(1) = -5+4
x(1) = -1
Hence x(1) = -1
You might be interested in
Answer:
Using the Law of Diminishing Marginal Utility, Jane would not be better off buying one more fry, since the marginal utility she obtains from the fries are lower when compared to the chicken sandwich; therefore, she would be better off ordering another chicken sandwich
Answer:
equation: 320+x=360, answer: 40
Step-by-step explanation:
add 100,200 and 100 to get 320
360-320=40
x=40
Answer:
friday
Step-by-step explanation:
8th day will be monday
then 32 nd will be monday.
so 36th is friday
4x + 4 + 4x = 180 so solve for x and it’s 22 1. 4x + 4 92 2. 88
The point-slope form:
We have the point (-3, -1) and the slope m = 3/5. Substitute:
Answer:
point-slope form: y + 1 = 3/5(x + 3)
slope-intercept form: y = 3/5x + 4/5
standard form: 3x - 5y = -4