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4 years ago

Which letter represents the activated complex? 1. A 2. B 3. F 4. G

Chemistry

1 answer:

lana66690 [7]4 years ago

4 0

Answer:

2. B.

Explanation:

The letter B represents the activated complex.

The activated complex is the intermediate that is formed between the states of reactants "F" and products "G".

Letter A represents the activation energy of the reaction, that is the difference in potential energy between the reactants "F" and activated complex "B".

Letter C represents the enthalpy change of the reaction, that is the difference in potential energy between products "G" and reactants "F".

Letter D represents the potential energy of products "G".

Letter E represents the potential energy of reactants "E".

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Consider the following equilibrium and the table of experimental data:

qaws [65]

Keq = products / reagents

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Keq = [ NO2 ]² / [ N2O4 ]

hope this helps!

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3 years ago

Diatomic iodine [I2] decomposes at high temperature to form I atoms according to the reaction I2(g)⇌2I(g), Kc = 0.011 at 1200∘C

umka2103 [35]

Answer:

The concentration of I at equilibrium = 3.3166×10⁻² M

Explanation:

For the equilibrium reaction,

I₂ (g) ⇄ 2I (g)

The expression for Kc for the reaction is:

$K_c=\frac {\left[I_{Equilibrium} \right]^2}{\left[I_2_{Equilibrium} \right]}$

Given:

$\left[I_2_{Equilibrium} \right]$ = 0.10 M

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Applying in the above formula to find the equilibrium concentration of I as:

$0.011=\frac {\left[I_{Equilibrium} \right]^2}{0.10}$

So,

$\left[I_{Equilibrium} \right]^2=0.011\times 0.10$

$\left[I_{Equilibrium} \right]^2=0.0011$

$\left[I_{Equilibrium} \right]=3.3166\times 10^{-2}\ M$

<u>Thus, The concentration of I at equilibrium = 3.3166×10⁻² M</u>

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4 years ago

When a scientist shares her findings with other scientists she is

finlep [7]

Answer:

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Explanation:

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4 years ago

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An atom has 24 protons, 22 electrons, and 28 neutrons. What is the IONIC CHARGE of the atom? *

aivan3 [116]

Answer:

-4

Explanation:

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3 years ago

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4 years ago