All categories

4 years ago

Which letter represents the activated complex? 1. A 2. B 3. F 4. G

Chemistry

1 answer:

lana66690 [7]4 years ago

4 0

Answer:

2. B.

Explanation:

The letter B represents the activated complex.

The activated complex is the intermediate that is formed between the states of reactants "F" and products "G".

Letter A represents the activation energy of the reaction, that is the difference in potential energy between the reactants "F" and activated complex "B".

Letter C represents the enthalpy change of the reaction, that is the difference in potential energy between products "G" and reactants "F".

Letter D represents the potential energy of products "G".

Letter E represents the potential energy of reactants "E".

You might be interested in

The columns in the periodic table are called groups. What do the elements in group 17 have in common?

natita [175]

Answer:

All of the elements in group 17 all have 7 valence electrons. This is one thing they all share in common.

Explanation:

7 0

3 years ago

A compound contains 36.48% Na, 25.41% S, and 38.11% O. Find it’s empirical formula

MAXImum [283]

Answer:

we can use 100g of compounds as the basis.

Explanation:

3 0

2 years ago

How many moles of water, H2O contain 2.0x10^22 molecules of water

Licemer1 [7]

I mole of water has an Avogadro number of molecules.

1 mole = 6.02 * 10^ 23 molecules.

6.02 * 10^ 23 molecules = 1 mole of water

1 molecule = 1/(6.02 * 10^23) mole of water

2.0 * 10^22 molecules would have = (2*10^22) * 1/(6.02*10^23)

= 0.033

2* 10 ^22 molecules of water would have 0.033 moles of water.

5 0

3 years ago

What volume of 3.00 MM HClHCl in liters is needed to react completely (with nothing left over) with 0.750 LL of 0.500 MM Na2CO3N

AlladinOne [14]

Answer: The volume of HCl needed is 0.250 L

Explanation:

To calculate the number of moles for given molarity, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}$

For sodium carbonate:

Molarity of sodium carbonate solution = 0.500 M

Volume of solution = 0.750 L

Putting values in above equation, we get:

$0.500M=\frac{\text{Moles of sodium carbonate}}{0.750}\\\\\text{Moles of sodium carbonate}=(0.500mol/L\times 0.750L)=0.375mol$

The chemical equation for the reaction of sodium carbonate and HCl follows:

$Na_2CO_3+2HCl\rightarrow 2NaCl+H_2CO_3$

By Stoichiometry of the reaction:

1 mole of sodium carbonate reacts with 2 moles of HCl

So, 0.375 moles of sodium carbonate will react with = $\frac{2}{1}\times 0.375=0.750mol$ of HCl

Now, calculating the volume of HCl by using equation 1:

Moles of HCl = 0.750 moles

Molarity of HCl = 3.00 M

Putting values in equation 1, we get:

$3.00M=\frac{0.750mol}{\text{Volume of solution}}\\\\\text{Volume of solution}=\frac{0.750mol}{3.00mol/L}=0.250L$

Hence, the volume of HCl needed is 0.250 L

8 0

3 years ago

3. How many grams of aluminum can be heated from 90°C to 120°C if 500 J of heat energy are applied?

IgorLugansk [536]

We are given:

Initial Temperature = 90°c

Final Temperature = 120°c

Heat applied(ΔH) = 500 Joules

Specific heat(c) = 0.9 Joules / g°C

Mass of Aluminium(m) = ?

Change in temperature:

ΔT = Final temp. - Inital Temp.

ΔT = 120 - 90

ΔT = 30°c

Calculating the mass:

We know the formula:

ΔH = mcΔT

replacing the values:

500 = m(0.9)(30)

500 = m(27)

m = 500/27

m = 18.52 grams

5 0

3 years ago