The disk method will only involve a single integral. I've attached a sketch of the bounded region (in red) and one such disk made by revolving it around the y-axis.
Such a disk has radius x = 1/y and height/thickness ∆y, so that the volume of one such disk is
π (radius) (height) = π (1/y)² ∆y = π/y² ∆y
and the volume of a stack of n such disks is
where 
is a point sampled from the interval [1, 5].
As we refine the solid by adding increasingly more, increasingly thinner disks, so that ∆y converges to 0, the sum converges to a definite integral that gives the exact volume V,
Answer:
Provide a question pls :)
Step-by-step explanation:
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Volume of water in the tank:
Differentiate both sides with respect to time <em>t</em> :
<em>V</em> changes at a rate of 2000 cc/min (cubic cm per minute); use this to solve for d<em>h</em>/d<em>t</em> :
(The question asks how the height changes at the exact moment the height is 50 cm, but this info is a red herring because the rate of change is constant.)
Answer:
The answer would be 7. By using PEMDAS 6 to the power of 2 equals 36. Then you divide 36 by 3 to get 12. The final step would be to subtract 5 from 12 to get 7. <u>So 7 is your answer</u><u>.</u>
Start by dividing both sides by 2:
5x + 6 = 5x + 6
Simplify:
0 = 0
This indicates infinite solutions:
x = All real numbers.
