What is the engine power of a car with 500N moving at constant speed 20ms-1
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Answer:
n = 4 x 10¹⁸ photons
Explanation:
First, we will calculate the energy of one photon in the radiation:
where,
E = Energy of one photon = ?
h = Plank's Constant = 6.625 x 10⁻³⁴ J.s
c = speed of light = 3 x 10⁸ m/s
λ = wavelength of radiation = 567 nm = 5.67 x 10⁻⁷ m
Therefore,
E = 3.505 x 10⁻¹⁹ J
Now, the number of photons to make up the total energy can be calculated as follows:
<u>n = 4 x 10¹⁸ photons</u>
The first question has the answer to your problem! I found the answer key!
To solve this problem we must consider the expressions of Stefan Boltzmann's law for which the rate of change of the radiation of energy H from a surface must be
Where
A = Surface area
e = Emissivity that characterizes the emitting properties of the surface
= Universal constant called the Stefan-Boltzmann constant
T = Absolute temperature
The total heat loss would be then
Therefore the net rate of heat loss from the body by radiation is 155.29J