Answer:
B. w=12.68rad/s
C. α=3.52rad/s^2
Explanation:
B)
We can solve this problem by taking into account that (as in the uniformly accelerated motion)
( 1 )
where w0 is the initial angular speed, α is the angular acceleration, s is the arc length and r is the radius.
In this case s=3.7m, r=16.2cm=0.162m, t=3.6s and w0=0. Hence, by using the equations (1) we have
to calculate the angular speed w we can use
Thus, wf=12.68rad/s
C) We can use our result in B)
I hope this is useful for you
regards
Answer:
3.42N
Explanation:
*not too sure bc i left my physics notes at school so it might not be 100% accurate :p*
Use the equation: F = (GMm)/(r^2)
F = force of gravity
G = gravitational constant (6.7x10^-11)
M = mass1 (2.5x10^30kg)
m = mass2 (1kg)
r = radius (7000m)
Plug it in: F = ((6.7x10^-11)(2.5x10^30)(1)) / (7000^2)
F = (1.675x10^20) / (4.9x10^7)
F = 3.4183673x10^12
F = 3.42N
D. used by the entire scientific community
B. more accurate system of measurement
Given: Velocity of light c = 3.00 x 10⁸ m/s
Frequency f = 7.65 x 10⁷/s
Required: Wavelength λ = ?
Formula: λ = c/f
λ = 3.00 x 10⁸ m/s/7.65 x 10⁷/s
λ = 3.92 m
