Answer:
F - fr = ma , N - W = 0
Explanation:
In this exercise we are asked to identify the forces that act on the jack, for this we will use Newton's second law
On the x axis
We have two forces: the friction and the force of the girl who pulls the cat
F - fr = ma
On the y axis
There are two forces: normal and weight
N - W = 0
A diagram of these forces can be seen in the attachment
Answer:
a = 2.72 [m/s2]
Explanation:
To solve this problem we must use the following kinematics equation:
where:
Vf = final velocity = 1200 [km/h]
Vo = initial velocity = 25 [km/h]
t = time = 2 [min] = 2/60 = 0.0333 [h]
1200 = 25 + (a*0.0333)
a = 35250.35 [km/h2]
if we convert these units to units of meters per second squared